Question

I have simple Login Controller. With in it, I have one action method called signIn(). I am submitting my credential to log into the website through ajax call.

This is my ajax caller function-

var AJAXCaller = function () {
};

AJAXCaller.prototype.call = function (type, uri, header, contentType, content, success, error) {
    var config = new SSKSConfig();
    var url = config.getLocation() + uri;
    return jQuery.ajax({
        'type': type,
        'url': url,
        'headers': header,
        'data': JSON.stringify(content),
        'success': success,
        'error': error
    });
};
var caller= new AJAXCaller();
caller.call('POST', '/login', { 'Content-Type': 'application/json' }, 'application/x-www-form-urlencoded', person, fnSuccess, fnError);

where 'person' data like -

{"emailId":"aaa@gmail.com","password":"12345"}

And login controller's signIn() method code is-

@PostMapping(value = "/login",consumes = MediaType.APPLICATION_JSON_VALUE)
    public String signIn(@RequestBody Person person) {
        if(person.getEmailId().equals("aaa@gmail.com") && person.getPassword().equals("12345")){
            return "Success";
        }
        else{
            return "Invalid";
        }
    }

I have created simple Person POJO class-

public class Person implements PersonSupport, AddressSupport {
    private String code;
    private String name;
    private String emailId;
    private String password;
    private String contactNo;
    private final Address address = new Address();

    public Person() {
    }

    @Override
    public void setCode(String code) {
        this.code = code;
    }

    @Override
    public String getCode() {
        return this.code;
    }

    @Override
    public void setName(String name) {
        this.name = name;
    }

    @Override
    public String getName() {
        return name;
    }

    @Override
    public void setContactNo(String contactNo) {
        this.contactNo = contactNo;
    }

    @Override
    public String getContactNo() {
        return contactNo;
    }

    @Override
    public void setEmailId(String emailId) {
        this.emailId = emailId;
    }

    @Override
    public String getPassword() {
        return this.password;
    }

    @Override
    public void setPassword(String password) {
        this.password = password;
    }

    @Override
    public String getEmailId() {
        return emailId;
    }

    @Override
    public String getRoadNo() {
        return address.getRoadNo();
    }

    @Override
    public String getRoadName() {
        return address.getRoadName();
    }

    @Override
    public String getCity() {
        return address.getCity();
    }

    @Override
    public String getPinCode() {
        return address.getPinCode();
    }

    @Override
    public StateList getStateList() {
        return address.getStateList();
    }

    @Override
    public void setRoadNo(String roadNo) {
        address.setRoadNo(roadNo);
    }

    @Override
    public void setRoadName(String roadName) {
        address.setRoadName(roadName);
    }

    @Override
    public void setCity(String city) {
        address.setCity(city);
    }

    @Override
    public void setPinCode(String pinCode) {
        address.setPinCode(pinCode);
    }

    @Override
    public void setStateList(StateList stateList) {
        address.setStateList(stateList);
    }

}

Now when i am try to login it gives me 415 Unsupported Media Type error. Can you help me why this error has occurred??? Thanks in advance..

Answer 1

您需要在jquery ajax调用中设置attr is: thisIsAttribute and the arguments are: element1 element2。

Answer 2

使用

@PostMapping(value = "/login",consumes = MediaType.APPLICATION_JSON_UTF8_VALUE)

由于数据将采用UTF编码，因此您必须使用此值或仅删除消耗部分

Answer 3

标题和内容类型的混合

$.ajax({
    type: type,
    url: url,
    data: JSON.stringify(content),
    contentType: "application/json; charset=utf-8",
    dataType: "json",
 ...
});

您通过了contentType ='application/x-www-form-urlencoded'。您仍然可以使用contentType变量但传递正确的值。在contentType的情况下无需使用标题。

Answer 4

从请求映射中删除consumes = MediaType.APPLICATION_JSON_VALUE，它应该开始工作。

Answer 5

谢谢。我已经解决了这个问题。我指定了 <mvc:annotation-driven/>，但我忘了提到将使用哪个HttpMessageConverter。我需要依赖杰克逊库（jackson-databind）以便我可以将HttpRequestBody转换为Person对象，现在，我可以支持MappingJackson2HttpMessageConverter。

Unsupported Media Type in Spring MVC

5 个答案: