Question

版本：python3.6.1

源代码：

class ContactList(list):
    def search(self,name):
    '''Return all contacts that contain the search value in their name.'''
        matching_contacts = []
        for contact in self:
            if name in contact.name:
                matching_contacts.append(contact)
            return matching_contacts

class Contact:
    all_contacts = ContactList()
    def __init__(self,name,email):
        self.name = name
        self.email = email
        Contact.all_contacts.append(self)

然后在IDLE

中运行它

c1 = Contact("John A","johna@example.com")
c2 = Contact("John B","johnb@example.com")
c3 = Contact("Jenna C","jennac@example.com")
[c.name for c in Contact.all_contacts.search('John')]

结果应为['John A','John B']，但我的空闲时间显示['John A']

我想知道我的代码有什么问题吗？

Answer 1

嗯，那是因为你的“回归”处于错误的位置。

class ContactList(list):
def search(self,name):
'''Return all contacts that contain the search value in their name.'''
    matching_contacts = []
    for contact in self:
        if name in contact.name:
            matching_contacts.append(contact)
    return matching_contacts

python OOP：扩展类

1 个答案: