我打算为商店存储工作时间。我想知道什么是工作时间字段的最佳建模,以便我能够以非常有效的方式获得当前时间的开放/封闭商店列表。
答案 0 :(得分:54)
要存储正常的营业时间,您需要存储一些包含以下内容的记录:
我假设每个商店在国定假日期间减少了工作时间,或者工厂停工,所以你还需要存储一些覆盖记录:
要找到开放式商店是微不足道的,但您还需要检查是否有覆盖时间:
SELECT Shop
FROM OverrideHours
WHERE OverrideStartDate <= NOW()
AND OverrideEndDate >= NOW()
AND DayOfWeek = WEEKDAY(NOW())
如果有任何记录返回,那些商店有交替的时间或已关闭。
你可以在这里做一些不错的SQL-fu,但这为你提供了基础知识。
修改强>
我没有对此进行测试,但这应该让你接近:
SELECT Normal.Shop
FROM Normal
LEFT JOIN Override
ON Normal.Shop = Override.Shop
AND Normal.DayOfWeek = Override.DayOfWeek
AND NOW() BETWEEN Override.OverrideStartDate AND Override.OverrideEndDate
WHERE Normal.DayOfWeek = WEEKDAY(NOW())
AND ((Override.Shop IS NULL AND TIME(NOW()) BETWEEN Normal.OpenTime AND Normal.CloseTime)
OR (Override.Shop IS NOT NULL AND Override.Closed <> 1 AND TIME(NOW()) BETWEEN Override.AltOpenTime AND Override.AltCloseTime))
修改强>
至于效率,从某种意义上来说,它只需要对MySQL进行一次调用就很有效,如果它通过网络通常是一个瓶颈。您必须测试并确定这是否符合您的规格。如果没有,你可能会玩一些指数。
修改强>
测试。不是完整的测试,而是一些。
mysql> select * from Normal;
+------+-----------+----------+-----------+
| Shop | DayOfWeek | OpenTime | CloseTime |
+------+-----------+----------+-----------+
| 1 | 1 | 09:00:00 | 17:00:00 |
| 1 | 5 | 09:00:00 | 16:00:00 |
| 2 | 1 | 09:00:00 | 17:00:00 |
| 2 | 5 | 09:00:00 | 17:00:00 |
+------+-----------+----------+-----------+
4 rows in set (0.01 sec)
mysql> select * from Override;
+------+-------------------+-----------------+-----------+-------------+--------------+--------+
| Shop | OverrideStartDate | OverrideEndDate | DayOfWeek | AltOpenTime | AltCloseTime | Closed |
+------+-------------------+-----------------+-----------+-------------+--------------+--------+
| 2 | 2010-12-01 | 2010-12-31 | 1 | 09:00:00 | 18:00:00 | 0 |
| 2 | 2010-12-01 | 2010-12-31 | 5 | 09:00:00 | 18:00:00 | 0 |
| 1 | 2010-12-01 | 2010-12-31 | 1 | 09:00:00 | 17:00:00 | 1 |
+------+-------------------+-----------------+-----------+-------------+--------------+--------+
3 rows in set (0.00 sec)
mysql> SET @whenever = TIMESTAMP('2010-11-23 16:05');
Query OK, 0 rows affected (0.00 sec)
mysql> SELECT WEEKDAY(@whenever);
+--------------------+
| WEEKDAY(@whenever) |
+--------------------+
| 1 |
+--------------------+
1 row in set (0.00 sec)
mysql> SELECT Normal.Shop FROM Normal LEFT JOIN Override ON Normal.Shop = Override.Shop AND Normal.DayOfWeek = Override.DayOfWeek AND @whenever BETWEEN Override.OverrideStartDate AND Override.OverrideEndDate WHERE Normal.DayOfWeek = WEEKDAY(@whenever) AND ((Override.Shop IS NULL AND TIME(@whenever) BETWEEN Normal.OpenTime AND Normal.CloseTime) OR (Override.Shop IS NOT NULL AND Override.Closed <> 1 AND TIME(@whenever) BETWEEN Override.AltOpenTime AND Override.AltCloseTime));
+------+
| Shop |
+------+
| 1 |
| 2 |
+------+
2 rows in set (0.00 sec)
mysql> SET @whenever = TIMESTAMP('2010-11-23 17:05');
Query OK, 0 rows affected (0.00 sec)
mysql> SELECT Normal.Shop FROM Normal LEFT JOIN Override ON Normal.Shop = Override.Shop AND Normal.DayOfWeek = Override.DayOfWeek AND @whenever BETWEEN Override.OverrideStartDate AND Override.OverrideEndDate WHERE Normal.DayOfWeek = WEEKDAY(@whenever) AND ((Override.Shop IS NULL AND TIME(@whenever) BETWEEN Normal.OpenTime AND Normal.CloseTime) OR (Override.Shop IS NOT NULL AND Override.Closed <> 1 AND TIME(@whenever) BETWEEN Override.AltOpenTime AND Override.AltCloseTime));
Empty set (0.01 sec)
mysql> SET @whenever = TIMESTAMP('2010-12-25 16:05');
Query OK, 0 rows affected (0.00 sec)
mysql> SELECT Normal.Shop FROM Normal LEFT JOIN Override ON Normal.Shop = Override.Shop AND Normal.DayOfWeek = Override.DayOfWeek AND @whenever BETWEEN Override.OverrideStartDate AND Override.OverrideEndDate WHERE Normal.DayOfWeek = WEEKDAY(@whenever) AND ((Override.Shop IS NULL AND TIME(@whenever) BETWEEN Normal.OpenTime AND Normal.CloseTime) OR (Override.Shop IS NOT NULL AND Override.Closed <> 1 AND TIME(@whenever) BETWEEN Override.AltOpenTime AND Override.AltCloseTime));
+------+
| Shop |
+------+
| 2 |
+------+
1 row in set (0.00 sec)
mysql> SET @whenever = TIMESTAMP('2010-11-23 17:05');
Query OK, 0 rows affected (0.00 sec)
mysql> SELECT WEEKDAY(@whenever);
+--------------------+
| WEEKDAY(@whenever) |
+--------------------+
| 1 |
+--------------------+
1 row in set (0.00 sec)
mysql> SELECT Normal.Shop FROM Normal LEFT JOIN Override ON Normal.Shop = Override.Shop AND Normal.DayOfWeek = Override.DayOfWeek AND @whenever BETWEEN Override.OverrideStartDate AND Override.OverrideEndDate WHERE Normal.DayOfWeek = WEEKDAY(@whenever) AND ((Override.Shop IS NULL AND TIME(@whenever) BETWEEN Normal.OpenTime AND Normal.CloseTime) OR (Override.Shop IS NOT NULL AND Override.Closed <> 1 AND TIME(@whenever) BETWEEN Override.AltOpenTime AND Override.AltCloseTime));
Empty set (0.00 sec)
答案 1 :(得分:9)
让我们考虑每周的所有营业时间都是一样的。那么下表呢?
为shop_id
标识的商店制作一张桌子,然后插入开放时间,即:
然后选择SELECT:
SELECT shop_id
FROM opening_hours
WHERE WEEKDAY(NOW()) = week_day
AND TIME(NOW()) BETWEEN opens_at AND closes_at