Question

我有商家和地址表以及数据透视表。

当用户点击他们想要查看的业务时，搜索业务ID并使用id我想获取它所属的地址的详细信息。所以我有这样的事情：

public function displayBusiness($id) {
    /*
    $business = Business::with('addresses')->find($id);
    $session = session()->put('key', $id);
    $gallery = Gallery::where('business_id', $id)->get();
    $location = Location::where('business_id', $id)->get();
    $review = Review::where('business_id', $id)->get();
        return view('displayBusiness', compact('business', 'address', 'gallery', 'location', 'review', 'items'));

}

我的商业模式：

public function addresses()
{
    return $this->belongsToMany('App\Address', 'business_address', 'business_id', 'address_id');
}

地址模型：

public function businesses()
{
    return $this->belongsToMany('App\Business', 'business_address', 'business_id', 'address_id');
}

在我看来：

<div class="container container2">
        <div id="left" class="logo2">
        <img class="images" id="image" src="{{ asset($business->image) }}" />
            <form class="upload_form" action="{{ action('ImageController@image') }}" enctype="multipart/form-data" role="form" method="POST">
            <input type="hidden" name="_token" value="{{ csrf_token() }}">
            <input style="width: 100%;height: 100%; opacity: 0;" name="img" id="img" class="img" data-input="false" type="file" data-buttonText="Upload Logo" data-size="sm" data-badge="false" onchange="submitImage();" />
                </form>
        </div>
<!-- Business Information -->
        <div class="info sortable">
        <input type="hidden" name="id" value="{{$business->id}}"/>

            <p>{{$business->name}}</p>
            <p>{{$business->email}}</p>
            <p>{{$business->addresses->firstline_address}}</p>
            <p>{{$business->addresses->secondline_address}}</p>
            <p>{{$business->addresses->town}}</p>
            <p>{{$business->addresses->city}}</p>
            <p>{{$business->addresses->postcode}}</p>
            <p>{{$business->addresses->telephone}}</p>
        </div>

但是我收到错误：

此集合实例上不存在属性[firstline_address]。

如何解决这个问题？

Answer 1

试试这个

$business->addresses()->value('firstline_address');

Answer 2

给定地址 - business是ManyToMany关系，地址是一个集合，所以请尝试

@foreach( $business->addresses as $address )
   <p>{{$address->firstline_address}}</p>
   .....
@endforeach

Answer 3

您不能$business->addresses->firstline_address，因为$business->addresses是地址的集合，而不是单个对象

您有两个选择：

选项1：foreach循环：

@forelse({{$business->addresses as $adresse)
    <p>{{$adresse->firstline_address}}</p>
        <p>{{$adresse->secondline_address}}</p>
        <p>{{$adresse->town}}</p>
        <p>{{$adresse->city}}</p>
        <p>{{$adresse->postcode}}</p>
        <p>{{$$adresse->telephone}}</p>
@empty
    <p> No Adresses </p>
@endforelse

选项2：您只需要第一个地址

        <p>{{$business->name}}</p>
        <p>{{$business->email}}</p>
        <p>{{$business->addresses->first()->firstline_address}}</p>
        <p>{{$business->addresses->first()->secondline_address}}</p>
        <p>{{$business->addresses->first()->town}}</p>
        <p>{{$business->addresses->first()->city}}</p>
        <p>{{$business->addresses->first()->postcode}}</p>
        <p>{{$business->addresses->first()->telephone}}</p>

Laravel雄辩的财产在这个系列中不存在

3 个答案: