Question

我有3个选择这样。我已经在sql中将所有3个选择转换为json。

public IHttpActionResult GetTest()
{
        string sql = $"SELECT 'Ahmad' AS N'Name',\n" +
        "1 AS N'Code',\n" +
        "0914 AS N'Phone' FOR JSON PATH\n" +
        "SELECT 'Alizadeh' AS N'NameFamily',\n" +
        "2 AS N'Code',\n" +
        "0915 AS N'Phone' FOR JSON PATH\n" +
        " \n" +
        " SELECT 'Seven' AS N'BookName',\n" +
        "3 AS N'Qty',\n" +
        "0916 AS N'IBS' FOR JSON PATH";
         var info = Connections.QueryMultiple(sql);
        return Ok(info);
 }

结果如下：

[
  {
    "Name": "Ahmad",
    "Code": 1,
    "Phone": 914
  },
  {
    "NameFamily": "Alizadeh",
    "Code": 2,
    "Phone": 915
  },
  {
    "BookName": "Seven",
    "Qty": 3,
    "IBS": 916
  }
]

Answer 1

全部阅读。

public IHttpActionResult GetTest()
{

    string sql = $"SELECT 'Ahmad' AS N'Name',\n" +
        "1 AS N'Code',\n" +
        "0914 AS N'Phone' FOR JSON PATH\n" +
        "SELECT 'Alizadeh' AS N'NameFamily',\n" +
        "2 AS N'Code',\n" +
        "0915 AS N'Phone' FOR JSON PATH\n" +
        " \n" +
        " SELECT 'Seven' AS N'BookName',\n" +
        "3 AS N'Qty',\n" +
        "0916 AS N'IBS' FOR JSON PATH";
    var info = Connections.SaleBranch.SqlConn.QueryMultiple(sql);
    var lstResult = new List<dynamic>();
    var isNext = false;
    do{
        var first2 = info.Read<dynamic>().Single();
        lstResult.Add(first2);
        isNext=info.IsConsumed;
    }
    while (!isNext);

    return Ok(lstResult);
}

Answer 2

如果您使用Azure / SQL2016或更高版本，则可以使用

FOR JSON 看到这篇文章： https://docs.microsoft.com/en-us/sql/relational-databases/json/format-query-results-as-json-with-for-json-sql-server

谁将Dapper结果QueryMultiple转换为mvc中的Json？

2 个答案: