Question

我的项目可以有一个projectOwner和多个projectMembers。创建项目后，我希望能够将用户添加到此项目中。

现在我的问题是我必须在创建新user_id时输入project_id和projectMember。该表单需要user_id和project_id，因此我如何更改它以便email，然后找到与其相关的user_id。

查看：

<%= form_for([@project, @project.project_members.build]) do |f| %>
  <p>
   <%= f.label :project_id %><br>
   <%= f.text_field :project_id %>
  </p>
  <p>
   <%= f.label :user_id %><br>
   <%= f.text_field :user_id %>
  </p>
  <p>
   <%= f.submit :Add, class: 'btn btn-info' %>
  </p>
<% end %>

控制器：

def create
  @project_member = ProjectMember.new(member_params)
  @project_member.save
end

private
  def member_params
    params.require(:project_member).permit(:user_id, :project_id)
  end

模型关系：

class  User < ApplicationRecord
  has_many :roles
  has_many :projects, through: :roles
end

class Role < ApplicationRecord
  belongs_to :user
  belongs_to :project
end

class ProjectOwner < Role
end

class ProjectMember < Role
end

class Project < ApplicationRecord
  has_many :project_members
  has_many :members, class_name: "User", through: :project_members
  has_one  :project_owner
  has_many :owners, class_name: "User", through: :project_owner
end

现在我的路线看起来像这样，但我觉得这不是正确的做法：

devise_for :users

resources :users do
  resources :projects
end

resources :projects do
  resources :project_members
end

Answer 1

表单需要user_id和project_id，所以我该如何更改这样它就会收到一封电子邮件，然后找到与之相关的user_id 它

您可以在格式的电子邮件中输入输入，并允许控制器完成其余操作

<%= form_for([@project, @project.project_members.build]) do |f| %> <%= f.label :project_id %> <%= f.text_field :project_id %> <%= label_tag :email %> <%= email_field_tag :email %> <%= f.submit :Add, class: 'btn btn-info' %> <% end %>

在控制器中，使用电子邮件找到用户

def create @project_member = ProjectMember.new(member_params) @user = User.find_by(email: params[:email]) @project_member.user_id = @user.id @project_member.save end

此外，您不需要在表单中明确提供project_id。表单中的@project会为您提供project_id。你只需要让控制器进行映射

<%= form_for([@project, @project.project_members.build]) do |f| %> <%= label_tag :email %> <%= email_field_tag :email %> <%= f.submit :Add, class: 'btn btn-info' %> <% end %>

在控制器中，

def create @project = Project.find(params[:project_id]) @project_member = @project.project_members.new(member_params) @user = User.find_by(email: params[:email]) @project_member.user_id = @user.id @project_member.save end

Answer 2

在您看来，将user_id替换为user_email字段：

 <p>
   <%= f.label :user_email %><br>
   <%= f.text_field :user_email %>
  </p>

在控制器中，获取email

def create
  user = User.find_by_email(params[:project_member][:user_email]) # find the user by email
  @project_member = ProjectMember.new(:project_id => params[:project_member][:project_id]) # create new project member with project id
  @project_member.users << user # assign user to newly created project member
  @project_member.save
end

private
  def member_params
    params.require(:project_member).permit(:user_email, :project_id)
  end

希望它有所帮助！

注意：请确保我们通过电子邮件找到的用户是否存在！

Answer 3

实现此目的的一种方法是将member_params修改为

def member_params
  member_params = params.require(:project_member).permit(:email, :project_id)
  if (user_id = User.find_by_email(member_params[:email]).try(:id)).present?
    member_params.merge!(user_id: user_id)
    member_params.permit!
  else
    # display error
  end
end

或者让你的params保持原样

def member_params
  params.require(:project_member).permit(:email, :project_id)
end

在你的控制器中，

def create
  @project_member = ProjectMember.build_by(member_params)
  if @project_member.save
    # success
  else
    # failure
  end
end

和模型，

def self.build_by(params)
  project_member = self.new(params)
  project_member.user_id = User.find_by_email(params[:email]).try(:id)
end

我认为，第二种选择更清洁，逻辑转向模型..

使用他的电子邮件将用户添加到项目

3 个答案: