Question

我在sql table Offer中有4列。

id (PK auto increment), name , org , TourCode Varchar(MAX)

TourCode包含逗号分隔的代码，例如（AVG123，JGH12等）。

我有40000 TourCode可用作逗号分隔值

我必须编写一个查询，在Offer表中插入4000行，每行包含10个用逗号分隔的游览代码。对于所有4000行，名称和组织的值保持相同，例如＆＃34; ABC＆＃34; ，＆＃34;亚马逊＆＃34;

e.g。

DECLARE @TourCodes VARCHAR(4000);
SET @TourCodes =  'AVG123,JGH12,AVasfG123,JGsdfH12,AVsdgG123,JsdgGH12 , A34G123,J56gGH12, A34G1df23,JgfGH12 ,......'

Output:
╦══════════╦════════════╦═══════════════════╗
║ name     ║ org        ║TourCode           ║
╠══════════╬═══════════ ╬═══════════════════╣
║      ABC ║     Amazon ║AVG123,JGH12       ║
║      ABC ║     Amazon ║AVasfG123,JGsdfH12 ║
║      ABC ║     Amazon ║AVsdgG123,JsdgGH12 ║
║      ABC ║     Amazon ║A34G123,J56gGH12   ║
║      ABC ║     Amazon ║A34G1df23,JgfGH12  ║

什么是我最好的方法。

我正在使用SQL Server。提前谢谢。

Answer 1

这是如何将逗号分隔值拆分为表格（取自How to split a comma-separated value to columns）

CREATE FUNCTION Split (
      @InputString                  VARCHAR(8000),
      @Delimiter                    VARCHAR(50)
)

RETURNS @Items TABLE (
      Item                          VARCHAR(8000)
)

AS
BEGIN
      IF @Delimiter = ' '
      BEGIN
            SET @Delimiter = ','
            SET @InputString = REPLACE(@InputString, ' ', @Delimiter)
      END

      IF (@Delimiter IS NULL OR @Delimiter = '')
            SET @Delimiter = ','

--INSERT INTO @Items VALUES (@Delimiter) -- Diagnostic
--INSERT INTO @Items VALUES (@InputString) -- Diagnostic

      DECLARE @Item           VARCHAR(8000)
      DECLARE @ItemList       VARCHAR(8000)
      DECLARE @DelimIndex     INT

      SET @ItemList = @InputString
      SET @DelimIndex = CHARINDEX(@Delimiter, @ItemList, 0)
      WHILE (@DelimIndex != 0)
      BEGIN
            SET @Item = SUBSTRING(@ItemList, 0, @DelimIndex)
            INSERT INTO @Items VALUES (@Item)

            -- Set @ItemList = @ItemList minus one less item
            SET @ItemList = SUBSTRING(@ItemList, @DelimIndex+1, LEN(@ItemList)-@DelimIndex)
            SET @DelimIndex = CHARINDEX(@Delimiter, @ItemList, 0)
      END -- End WHILE

      IF @Item IS NOT NULL -- At least one delimiter was encountered in @InputString
      BEGIN
            SET @Item = @ItemList
            INSERT INTO @Items VALUES (@Item)
      END

      -- No delimiters were encountered in @InputString, so just return @InputString
      ELSE INSERT INTO @Items VALUES (@InputString)

      RETURN

END -- End Function
GO

之后

使用此代码

DECLARE @TourCodes  varchar(4000)
SET @TourCodes  = 'AAAAA,BBBBB,CCCCC,DDDD,EEEE,FFFF , GGG,HHHHH, IIIII,JJJJJ'

DECLARE @T as table (ID int identity, Name varchar(255), Org varchar(255), TourCode varchar(255))

INSERT @T (Name, Org, TourCode)
select 'ABC', 'AMAZON', Item from dbo.split(@TourCodes,',')


Select A.Name, A.Org, ISNULL(A.TourCode, '') + ',' + ISNULL(B.TourCode, '')
from @T A INNER JOIN @T B
ON A.ID = B.ID-1
AND A.ID%2 = 0

Answer 2

那么这个解决方案呢？

DECLARE @TourCodes VARCHAR(4000);
SET @TourCodes =  ' AVG123   , JGH12,AVasfG123,JGsdfH12,AVsdgG123,JsdgGH12 , A34G123,J56gGH12, A34G1df23,JgfGH12';

with rcrs AS (
select rtrim(ltrim(LEFT(@TourCodes,charindex(',',@TourCodes)-1))) first,     
       SUBSTRING(@TourCodes+',',charindex(',',@TourCodes)+1,4000) other,
       0 flg
union all
select rtrim(ltrim(LEFT(other,charindex(',',other)-1))) first,
       SUBSTRING(other,charindex(',',other)+1,4000) other ,
       flg+1 flg FROM rcrs WHERE charindex(',',other)>0

) 
SELECT a.first one,b.first two from rcrs a 
INNER JOIN rcrs b ON b.flg=a.flg+1 WHERE a.flg%2=0

在递归CTE中，字符串从头开始分割。

值得注意的是，我在递归CTE的第一部分中加了一个额外的','的原始字符串。这可以确保所有单词都被“吃掉”＃34;通过CTE，主要选择可以使用模（%）技巧处理，以确定哪个部分进入列one或two。

此示例的结果是：

one       two

AVG123    JGH12
AVasfG123 JGsdfH12
AVsdgG123 JsdgGH12
A34G123   J56gGH12
A34G1df23 JgfGH12

点击此处查看演示：http://rextester.com/WAA6224

修改

我显然有太多时间在我手上;-) ...
所以我继续尝试是否可以按照OP似乎想要的方式将整个内容重新组合成十列集合。我仍然不完全清楚结果是如何看的，但这是另一个镜头：

DECLARE @TourCodes VARCHAR(4000); SET @TourCodes = REPLACE(REPLACE( ' AVG123 , JGH12,AVasfG123,JGsdfH12,AVsdgG123,JsdgGH12 , A34G123,J56gGH12, A34G1df23,JgfGH12, AVG1234 , JGH126,AVasfG1238,JGsdfH122,AVsdgG1235,JsdgGH127 , A34G1239,J56gGH12a, A34G1df23c,JgfGH12e, AVG1235 , JGH127,AVasfG1239,JGsdfH123,AVsdgG1236,JsdgGH128 , A34G1230,J56gGH12b, A34G1df23d,JgfGH12f', char(10),''),char(13),''); -- this is just a slightly extended sample input string with rcrs AS ( select rtrim(ltrim(LEFT(@TourCodes,charindex(',',@TourCodes)-1))) first, SUBSTRING(@TourCodes+',',charindex(',',@TourCodes)+1,4000) other, 0 flg union all select rtrim(ltrim(LEFT(other,charindex(',',other)-1))) first, SUBSTRING(other,charindex(',',other)+1,4000) other , flg+1 flg FROM rcrs WHERE charindex(',',other)>0 and flg<30 ), cmbn AS ( SELECT a.flg/20 ii,(a.flg/2)%10 ij ,a.first+','+b.first tc FROM rcrs a LEFT JOIN rcrs b ON b.flg=a.flg+1 WHERE a.flg%2=0 ) SELECT ii,'ABC' name,'Amazon' org, MAX(CASE ij WHEN 0 THEN tc END) tc1, MAX(CASE ij WHEN 1 THEN tc END) tc2, MAX(CASE ij WHEN 2 THEN tc END) tc3, MAX(CASE ij WHEN 3 THEN tc END) tc4, MAX(CASE ij WHEN 4 THEN tc END) tc5, MAX(CASE ij WHEN 5 THEN tc END) tc6, MAX(CASE ij WHEN 6 THEN tc END) tc7, MAX(CASE ij WHEN 7 THEN tc END) tc8, MAX(CASE ij WHEN 8 THEN tc END) tc9, MAX(CASE ij WHEN 9 THEN tc END) tc10 FROM cmbn GROUP BY ii

结果如下：

ii name org tc1 tc2 tc3 tc4 tc5 tc6 tc7 tc8 tc9 tc10 0 ABC Amazon AVG123,JGH12 AVasfG123,JGsdfH12 AVsdgG123,JsdgGH12 A34G123,J56gGH12 A34G1df23,JgfGH12 AVG1234,JGH126 AVasfG1238,JGsdfH122 AVsdgG1235,JsdgGH127 A34G1239,J56gGH12a A34G1df23c,JgfGH12e 1 ABC Amazon AVG1235,JGH127 AVasfG1239,JGsdfH123 AVsdgG1236,JsdgGH128 A34G1230,J56gGH12b A34G1df23d,JgfGH12f

见这里：http://rextester.com/ZJNV34690

或者，如果你想要在一列中的所有十个旅行代码你可以做

SELECT ii,'ABC' name,'Amazon' org, MAX(CASE ij WHEN 0 THEN tc END)+' '+ COALESCE(MAX(CASE ij WHEN 1 THEN tc END)+' ','')+ COALESCE(MAX(CASE ij WHEN 2 THEN tc END)+' ','')+ COALESCE(MAX(CASE ij WHEN 3 THEN tc END)+' ','')+ COALESCE(MAX(CASE ij WHEN 4 THEN tc END)+' ','')+ COALESCE(MAX(CASE ij WHEN 5 THEN tc END)+' ','')+ COALESCE(MAX(CASE ij WHEN 6 THEN tc END)+' ','')+ COALESCE(MAX(CASE ij WHEN 7 THEN tc END)+' ','')+ COALESCE(MAX(CASE ij WHEN 8 THEN tc END)+' ','')+ COALESCE(MAX(CASE ij WHEN 9 THEN tc END)+' ','') tourCodes FROM cmbn GROUP BY ii

在主要选择中。见http://rextester.com/AQCG28977

结果：

ii name org tourCodes 0 ABC Amazon AVG123,JGH12 AVasfG123,JGsdfH12 AVsdgG123,JsdgGH12 A34G123,J56gGH12 A34G1df23,JgfGH12 AVG1234,JGH126 AVasfG1238,JGsdfH122 AVsdgG1235,JsdgGH127 A34G1239,J56gGH12a A34G1df23c,JgfGH12e 1 ABC Amazon AVG1235,JGH127 AVasfG1239,JGsdfH123 AVsdgG1236,JsdgGH128 A34G1230,J56gGH12b A34G1df23d,JgfGH12f

Answer 3

然后首先尝试使用分号

分割SP

此函数将以分号

分隔每N个Tours数

create FUNCTION GroupBySemicolon (
      @TourCodes                  VARCHAR(8000),
      @HowManyTours               int
)

RETURNS varchar(8000)
AS
BEGIN


DECLARE @i int
DECLARE @Pos int

SET @i = 0
SET @Pos = 1
WHILE @Pos <> 0
BEGIN
    SET @i= @i+1
    SET @Pos = CHARINDEX( ',', @TourCodes,@Pos + 1)
    --SELECT @Pos
    IF @i = @HowManyTours and @Pos > 0
    BEGIN
        SET @i = 0

        SET @TourCodes = LEFT(@TourCodes,@Pos-1) + ';' + RIGHT(@TourCodes, LEN(@TourCodes) - @Pos)
    END

END




RETURN @TourCodes

END

select dbo.GroupBySemicolon( '111,222222,333,44,555555,66 ,7777,8888, 99999,000000', 4)

读取逗号分隔值并批量插入SQL表

3 个答案: