Question

我正在处理CSV文件，其中一列是具有数组格式的字符串的单元格。以下是访问这些单元格的内容：

$csv = Import-Csv $filelocation
foreach ($line in $csv)
{
   Write-Host $line.ColumnName
}

输出：

[Property=[value1,value2,value3]]
[Property=[value1,value2]]
...

您可以看到每个单元格都输出一个带有数组结构的字符串。我想将每个单独的字符串视为具有Property[0] = value1等的数组

有一种简单的方法吗？否则，我认为我需要使用Reg Ex。

Answer 1

哦！抱歉...没有看到文件内容：,,,,,“[AsymmetricKey = []]”，“[AppAddress = [[AddressType = Reply，A ddress = urn：ietf：wg：o auth：2.0： OOB]]]”， “[A ppAuxiliaryId = []]” ,, ,, 好的...如果像这样的所有文件内容，我们可以做类似的事情：

$ patch = get-content'D：\ test \ testing！.csv'

$pl = $patch.Length - 1

for ($i=0 ; $i -le $pl ; $i++) {

$patch[$i].Replace(",,,,,","").Replace(",,‌,,","").Replace("Reply,A‌ddress","Reply.A‌ddress").Split(",")[0]
$patch[$i].Replace(",,,,,","").Replace(",,‌,,","").Replace("Reply,A‌ddress","Reply.A‌ddress").Split(",")[1]
$patch[$i].Replace(",,,,,","").Replace(",,‌,,","").Replace("Reply,A‌ddress","Reply.A‌ddress").Split(",")[2]
$patch[$i].Replace(",,,,,","").Replace(",,‌,,","").Replace("Reply,A‌ddress","Reply.A‌ddress").Split(",")[3]
}

Answer 2

如果您想搜索某些信息，请认为它可以正常工作（但不确定）：

$ patch = get-content'D：\ test \ testing！.csv'       $ pl = $ patch.Length - 1
for ($i=0 ; $i -le $pl ; $i++) {

$regex = "urn:ietf:wg:o‌auth:2.0:o2b"

$val = $patch[$i].Replace(",,,,,","").Replace(",,‌,,","").Replace("Reply,A‌ddress","Reply.A‌ddress").Split(",")[1]
  if ($val.Contains($regex)) 
  {
 $val
 }
}

Answer 3

你尝试做这样的事情：

$csv = Import-Csv Path:\testing!.csv -Header V1

foreach ($line in $csv) {
    $obj = New-Object -TypeName PSObject -Property @{
        First = $line
    } #| select First #
    @{Name='First';Expression={($_.First).Split(";")[1]}}
    $obj1 = $obj | select -ExpandProperty First
    $obj1.V1
}

你可以将带括号和数组格式的字符串转换为数组吗？

3 个答案: