Question

我正在尝试创建一个RPG游戏，我正在使代码更简洁。我遇到了一个我无法解决的问题，我也做了一些研究，但我似乎无法解决它。

我将主要代码DragonFightingRPG.py与我在同一目录（prints.py和options.py）中导入的其他文件一起使用。我正在尝试从另一个文件导入一个列表，因此它可以检查用户是否输入了其中一个答案，并且可以相应地回答。

DragonFightingRPG.py

import prints
import options

class Player(object):
    def __init__(self):
        self.name = None
        self.gold = None
        self.maxhealth = 100
        self.health = 100

    def get_name(self):
        self.name = input("Hey there! What's your name?\n~~> ")
        print("Nice name, {0}!".format(self.name))

    def give_gold(self):
        print("Since you are new around here, 100 gold doubloons have been given to you!")
        self.gold = 100

    def gold_counter(self):
        print("You currently have {0} gold!".format(player.gold))



player = Player()


def start():
    player.get_name()
    player.give_gold()
    gold_counter()
    prints.intro()


def gold_counter():
    while True:
        option = input("Do you want to see your balance?\n~~> ").upper()
        if option in {options.yes_opt}:
            print("You currently have {0} gold.".format(player.gold))
        elif option in {options.no_opt}:
            print("You can check your balance later in the game.")
        else:
            print("Please try again.")
            continue
        break





start()

prints.py

class Player(object):
    def __init__(self):
        self.name = None
        self.gold = None
        self.maxhealth = 100
        self.health = 100

    def get_name(self):
        self.name = input("Hey there! What's your name?\n~~> ")
        print("Nice name, {0}!".format(self.name))

    def give_gold(self):
        print("Since you are new around here, 100 gold doubloons have been given to you!")
        self.gold = 100

    def gold_counter(self):
        print("You currently have {0} gold!".format(player.gold))

def intro():
    print("Narrator: Uhhhm...")
    print("N: Let me check my list...")
    print("N: Ah! Yes! {0}, that's right. I heard you were supposed to be arriving today.".format(player.name))
    print("N: Welcome to... THE DRAGON FIGHTER GAME!")
    print("N: I know, it isn't the most imaginative name.")
    print("N: Don't look at me like that, I tried my hardest!")
    print("N: Anywho, let's carry on.")
    print("N: For some stupid reason, the creator of this game didn't give me an actual name, so\nmy name is just \"Narrator\" or \"N\".")
    print("N:")

player = Player()

options.py

def yes_opt():
    {"Y", "YE", "YES", "YEAH", "PLEASE", "YES PLEASE"}

def no_opt():
    {"N", "NO", "NOPE"}

我正在努力的部分是elif option in {options.no_opt}:和if option in {options.yes_opt}:。如果我只在主代码中输入列表，它可以工作，但我想尝试从其他文件导入它。有什么想法吗？

Answer 1

只需进行一些小改动，就可以实现这一目标。

options.py

您应该从方法中返回这些集。

def yes_opt():
    return {"Y", "YE", "YES", "YEAH", "PLEASE", "YES PLEASE"}

def no_opt():
    return {"N", "NO", "NOPE"}

在DragonFightingRPG.py中，您将from options import yes_opt, no_opt指定为导入语句。

当你调用这些函数时，它们将返回相应的集合。

if option in yes_opt():

等等。

Answer 2

def yes_opt():
    {"Y", "YE", "YES", "YEAH", "PLEASE", "YES PLEASE"}

这定义了一个名为yes_opt的函数（实际上什么都不做），而不是一个带有该名称的 set 。

因此，option in yes_opt不起作用。

你可能只想写这个：

yes_opt = {"Y", "YE", "YES", "YEAH", "PLEASE", "YES PLEASE"}

如何从导入文件中的函数导入列表？

2 个答案: