在VBA中,我正在编写一个简单的脚本,记录正在使用的电子表格版本。
Private Sub Workbook_Open()
version = "1.0"
Set objHTTP = CreateObject("WinHttp.WinHttpRequest.5.1")
URL = "<WEB SERVICE>"
objHTTP.Open "POST", URL, False
objHTTP.setRequestHeader "User-Agent", "Mozilla/4.0 (compatible; MSIE 6.0; Windows NT 5.0)"
objHTTP.setRequestHeader "Content-type", "application/x-www-form-urlencoded"
objHTTP.send ("version=" + version)
End Sub
流程工作找到。
我正在尝试捕获,所以如果Web主机处于脱机状态,而不是显示运行时错误,我会抓住它并禁止它。
在VBA中尝试catch的最佳方法是什么,因此没有显示错误消息?
答案 0 :(得分:20)
Private Sub Workbook_Open()
on error goto Oops
version = "1.0"
Set objHTTP = CreateObject("WinHttp.WinHttpRequest.5.1")
URL = "<WEB SERVICE>"
objHTTP.Open "POST", URL, False
objHTTP.setRequestHeader "User-Agent", "Mozilla/4.0 (compatible; MSIE 6.0; Windows NT 5.0)"
objHTTP.setRequestHeader "Content-type", "application/x-www-form-urlencoded"
objHTTP.send ("version=" + version)
exit sub
Oops:
'handle error here
End Sub
例如,如果您想要因错误而更改URL,则可以执行此操作
Private Sub Workbook_Open()
on error goto Oops
version = "1.0"
Set objHTTP = CreateObject("WinHttp.WinHttpRequest.5.1")
URL = "<WEB SERVICE>"
Send:
objHTTP.Open "POST", URL, False
objHTTP.setRequestHeader "User-Agent", "Mozilla/4.0 (compatible; MSIE 6.0; Windows NT 5.0)"
objHTTP.setRequestHeader "Content-type", "application/x-www-form-urlencoded"
objHTTP.send ("version=" + version)
exit sub
Oops:
'handle error here
URL="new URL"
resume Send 'risk of endless loop if the new URL is also bad
End Sub
另外,如果你的感觉真的尝试/吸引人,你可以仿效这样。
Private Sub Workbook_Open()
version = "1.0"
Set objHTTP = CreateObject("WinHttp.WinHttpRequest.5.1")
URL = "<WEB SERVICE>"
on error resume next 'be very careful with this, it ignores all errors
objHTTP.Open "POST", URL, False
objHTTP.setRequestHeader "User-Agent", "Mozilla/4.0 (compatible; MSIE 6.0; Windows NT 5.0)"
objHTTP.setRequestHeader "Content-type", "application/x-www-form-urlencoded"
objHTTP.send ("version=" + version)
if err <> 0 then
'not 0 means it errored, handle it here
err.clear 'keep in mind this doesn't reset the error handler, any code after this will still ignore errors
end if
End Sub
因此,将此扩展为真正的核心......
Private Sub Workbook_Open()
version = "1.0"
on error resume next
Set objHTTP = CreateObject("WinHttp.WinHttpRequest.5.1")
if err <> 0 then
'unable to create object, give up
err.clear
exit sub
end if
URL = "<WEB SERVICE>"
objHTTP.Open "POST", URL, False
if err <> 0 then
'unable to open request, give up
err.clear
exit sub
end if
objHTTP.setRequestHeader "User-Agent", "Mozilla/4.0 (compatible; MSIE 6.0; Windows NT 5.0)"
objHTTP.setRequestHeader "Content-type", "application/x-www-form-urlencoded"
objHTTP.send ("version=" + version)
if err <> 0 then
'unable to send request, give up
err.clear
exit sub
end if
End Sub
另外值得注意的是,on error goto
样式中发生的任何错误都不会被处理,所以如果你这样做了
private sub MakeError()
dim iTemp as integer
on error goto Oops
iTemp = 5 / 0 'divide by 0 error
exit sub
Oops:
itemp = 4 / 0 'unhandled exception, divide by 0 error
end sub
会导致未处理的异常,但是
private sub MakeError()
dim iTemp as integer
on error resume next
iTemp = 5 / 0 'divide by 0 error
if err <> 0 then
err.clear
iTemp = 4 / 0 'divide by 0 error, but still ignored
if err <> 0 then
'another error
end if
end if
end sub
不会导致任何异常,因为VBA忽略了所有异常。
答案 1 :(得分:3)
类似这样的东西:
Try
...
Catch (Exception e)
...
End Try
在VBA中可能看起来像这样:
' The "Try" part
On Error Resume Next
...
On Error GoTo 0
' The "Catch" part
If Err.Number <> 0 Then
...
End If
但是,此表格可能未遵循最佳做法。