这是我的问题:
SELECT loc.id, loc.nom, loc.prenom, loc.num_tel, loc.num_fixe, bat.adresse, b.date_entree, b.date_sortie, p.date FROM locataires AS loc, bail AS b, apparts AS ap, batiments as bat, clients as cli, paye as p WHERE loc.id = b.idloc AND b.idappart = ap.id AND ap.idbat = bat.id AND bat.idcli = cli. id AND loc.id = b.idloc AND ap.id = b.idappart AND p.idloc = loc.id AND cli.email ="ben@test.be"
此查询提供:
但我想要每个人的最后日期(最多(p.date))
(注意:有人住在同一栋楼里,这就是为什么有些人有相同的地址)
请问好吗?
答案 0 :(得分:1)
试试这个。所有其他列都Max(p.date)
Group By
。
SELECT loc.id, loc.nom, loc.prenom, loc.num_tel, loc.num_fixe, bat.adresse,
b.date_entree, b.date_sortie, MAX(p.date) as Date
FROM locataires AS loc, bail AS b, apparts AS ap,
batiments as bat, clients as cli, paye as p
WHERE loc.id = b.idloc AND b.idappart = ap.id AND ap.idbat = bat.id
AND bat.idcli = cli. id AND loc.id = b.idloc
AND ap.id = b.idappart AND p.idloc = loc.id
AND cli.email ="ben@test.be"
Group By loc.id, loc.nom, loc.prenom, loc.num_tel, loc.num_fixe, bat.adresse,
b.date_entree, b.date_sortie