SubForm enumeration in priority-web-sdk

时间:2017-06-19 13:55:44

标签: javascript erp

I'm enumerating forms / subforms like so:

var pdqFormLoad = function(form) {
    if (form) {
        var
            i,
            col,
            subf
            ;

        console.log("Opened form [%s].", form.title);

        console.log("\nColumns of $s.", form.title);
        for (i in form.columns) {
            col = form.columns[i];
            console.log("  -- %j", col);
        };

        console.log("\nSubforms of %s.", form.title);
        for (subf in form.subForms) {
            console.log(
                "  -- Opening subform %s.",
                subf
            );
            pdq.startForm(form, subf, pdqFormLoad);
        };

    }
    else {
        console.log("No form.");

    };
};

Firstly I note that only the title attribute is provided. Unfortunately the "formName" parameter of the startSubForm function requires the internal form name, rather than the title descriptor.

/* Debug output */
Connectiong to https://www.eshbelsaas.com/ui/.
Opening form [ORDERS] in company [usdemo].
Opened form [Sales Orders].

Subforms of Sales Orders.
  --Opening subform
    {"title":"Attachments"}.

So I wasn't expecting the subsequent call to startSubForm to work:

pdq.subForm = function (FormName, pdqFormLoad) {

    console.log("Opening subform [%s] in company [%s].", FormName, _config.company);

    eventEmitter.on('pdqFormLoad', pdqFormLoad);
    priority.startSubForm(FormName, pdq.ErrorCallback, pdq.onUpdateFields).then(
        function (form) {        
            eventEmitter.emit('pdqFormLoad', form);

        },

        function () {
            eventEmitter.emit('pdqFormLoad', null);

        }
    );
}

What I wasn't expecting was for the package to deny all knowledge of the function:

Opening subform [Attachments] in company [usdemo].
(node:38560) UnhandledPromiseRejectionWarning: 
Unhandled promise rejection (rejection id: 1): 
TypeError: priority.startSubForm is not a function

Any suggestions please @NeomiBushary, @Leor?


Update 2: Ok, I'm now receiving the Sub-form ID and passing it to my function, along with the parent form, if any exists like this:

pdq.startForm = function (parent, FormName, pdqFormLoad) {

    eventEmitter.on('pdqFormLoad', pdqFormLoad);

    if (parent) {
        console.log("Parent form.\n%j", parent);
        parent.startSubForm(FormName, pdq.ErrorCallback, pdq.onUpdateFields).then(
            function (subform) {
                console.log("Sub form.\n%j", subform);
                eventEmitter.emit('pdqFormLoad', subform);

            },

            function () {
                eventEmitter.emit('pdqFormLoad', null);

            }
        );

    } else {
        priority.formStart(
            FormName,
            pdq.ErrorCallback,
            pdq.onUpdateFields,
            _config.company,
            0
        ).then(
            function (form) {
                eventEmitter.emit('pdqFormLoad', form);

            },

            function () {
                eventEmitter.emit('pdqFormLoad', null);

            }
        );

    };

}

This works for the call to formStart (parent==null). But when I call the startSubForm on the parent form (created by the formstart call), the resulting form object passed to the [onSuccsess] event is the parent form, not the requested sub-form.

An example...

parent.startSubForm("EXTFILES" ...

where parent is a form object created by formStart with parent.name = "ORDERS"

...then(
            function (subform) {

subform.name is also = "ORDERS"

Any ideas please?


Update 3:

Here's the parent / returned sub-form objects.

Parent form.

{
  "name": "ORDERS",
  "title": "Sales Orders",
  "subForms": {
    "EXTFILES": { "title": "Attachments" },
    ...
  },
  "activations": {
    ...
  },
  "columns": {
    ...
  },
  "oneline": 0,
  "isquery": 0,
  "ishtml": 0
}

Sub form.

{
  "name": "ORDERS",
  "title": "Sales Orders",
  "subForms": {
    "EXTFILES": { "title": "Attachments" },
    ...
  },
  "activations": {
    ...
  },
  "columns": {
    ...
  },
  "oneline": 0,
  "isquery": 0,
  "ishtml": 0
}


Update 4

Another example of a call to startSubForm returning the parent form, rather than the requested subform...

    function thisapp(){
        return new Promise((resolve, reject) => {
            formStart('APPGEN', showMessage, updateFields).then(
                function (appgen) {

                    var thisQuery = QueryValue();
                    thisQuery.field="APPNAME";
                    thisQuery.fromval=config.appname;

                    var f = FilterValue();
                    f.QueryValues.push(thisQuery);

                    appgen.Filter = f;
                    appgen.getRows(0).then(
                        function(rows) {
                            appgen.setActiveRow(1);
                            resolve(appgen);
                        },
                        function(message){
                            reject(message)
                        }
                    )                   
                },

                function(message){
                    reject(message)
                }

            )

        });
    };

    function appForms(appgen, formName){
        return new Promise((resolve, reject) => {
            appgen.startSubForm("APPFORMS", showMessage, updateFields).then(
                function (appforms) {

                    var thisQuery = QueryValue();
                    thisQuery.field="FATENAME";
                    thisQuery.fromval=formName;

                    var f = FilterValue();
                    f.QueryValues.push(thisQuery);

                    appforms.Filter = f;
                    resolve(appforms);
                },

                function(message){
                    reject(message)
                }

            )
        });
    };

    function priorityReady() {

        login(config).then(
            function(){
                thisapp().then(
                    function(appgen){
                        appForms(appgen, "DOCUMENTS_Q").then(
                            function(appforms){
                                appforms.getRows(0).then(
                                    function(rows) {
                                        console.log(rows);
                                    }, showMessage
                                )
                            }, showMessage
                        )
                    }, showMessage
                )
            }, showMessage
        )

    }

1 个答案:

答案 0 :(得分:0)

我将逐一回答这两个问题:

首先,打开的subForms对象上存在的form属性是一个javascript对象,其中键是内部子表单名称,值是带有子表单标题的对象。

for (subformName in form.subForms) {                        
     console.log("--Opening subform: " + subformName);
}

将输出:

Subforms of Sales Orders.
  --Opening subform EXTFILES

为了检索包含子表单所有属性的form对象,您必须使用startSubForm启动子表单。

其次,startSubForm函数是form检索的父formStart对象的实例方法。它不是优先级模块的全局方法。

所以你应该这样做:

formStart('ORDERS',...)
  .then(function(form) {//retrieve the parent form object
     form.startSubForm('EXTFILES') //start a subform for that form
      .then(function(subform) { ...}
  });

startSubForm为特定表单启动子表单,这就是为什么应该在其父表单的特定form对象上调用它。要启动子子表单,应在startSubForm对象等上调用subform

通常我会提到为特定表单执行操作的所有方法都是form对象的实例方法。可用实例方法的列表记录在here