我有一个选择菜单选项,我以这种方式获得城市:
select ID from $wpdb->posts where post_type = 'place' and post_parent = $cities order by post_title asc
问题在于,有不止一次展示的城镇,例如柏林柏林柏林"。如何使用sql查询删除重复的城镇?
这是整个文件:
public static function get_destination_countries() {
global $wpdb;
$countries = $wpdb->get_results( "select ID, post_title from $wpdb->posts where post_type = 'place' and post_parent = 0 order by post_title asc ", ARRAY_A );
return $countries;
}
/**
* Fetch all destination states by a country
*
* @return array all states by a country, array with post_ID and post_title
*/
public static function get_destination_states( $country_id ) {
global $wpdb;
if(!empty($country_id)){
// We need to make sure the destination state has ACF "state"
$place_type_tax_id = '';
$place_type_tax = get_term_by( 'slug', 'state', 'place-type' );
if ( ! empty( $place_type_tax ) && ! is_wp_error( $place_type_tax ) ) {
$place_type_tax_id = $place_type_tax->term_id;
}
//$states = $wpdb->get_results( "select ID, post_title from $wpdb->posts where post_type = 'place' and post_parent = $country_id order by post_title asc", ARRAY_A );
$states = $wpdb->get_results( "select p.ID , p.post_title, pm.meta_value from $wpdb->postmeta pm inner join $wpdb->posts p where p.post_parent = $country_id and p.ID = pm.post_id and meta_value = '$place_type_tax_id' order by post_title asc" , ARRAY_A );
return $states;
}
return false;
}
/**
* Get a list of all cities in a State
*/
public static function get_cities_from_state( $state_id ) {
global $wpdb;
if(!empty($state_id)){
$cities = $wpdb->get_col( "select ID from $wpdb->posts where post_type = 'place' and post_parent = $state_id order by post_title asc" );
return $cities;
}
return false;
}
/**
* Pull up a country ID by name - helpful to get United States as an ID in any DB
*/
public static function get_destination_country_id_by_name( $country_name ) {
global $wpdb;
if(!empty($country_name)){
$country_id = $wpdb->get_var( "select ID from $wpdb->posts where post_type = 'place' and post_title = '$country_name' order by post_title asc " );
return $country_id;
}
return false;
}
/**
* Pull destination's (countries, states etc) name by place ID
*/
public static function get_destination_name_by_id( $place_id ) {
global $wpdb;
if(!empty($place_id)){
$destination_name = $wpdb->get_var( "select post_title from $wpdb->posts where post_type = 'place' and ID = $place_id order by post_title asc" );
return $destination_name;
}
return false;
}
/**
* Fetch the country ID by state ID being a parent - used for the results page
*/
public static function get_country_by_state_id( $place_id ) {
global $wpdb;
if(!empty($place_id)){
$parent_id = $wpdb->get_var( "select post_parent from $wpdb->posts where post_type = 'place' and ID = $place_id order by post_title asc" );
return $parent_id;
}
return false;
}
/**
* Needed for the destination results page
*
* Fetch all destinations attached through ACF via state
*/
public static function get_destination_ids_by_state( $state_id ) {
}
/**
* Get destinations in a list of cities, TBD
*/
public static function get_destinations_in_cities( $cities ) {
global $wpdb;
if(!empty($cities)){
$cities = $wpdb->get_col( "select ID from $wpdb->posts where post_type = 'place' and post_parent = $cities order by post_title asc" );
return $cities;
}
return false;
}
答案 0 :(得分:0)
尝试:
select DISTINCT(ID) from $wpdb->posts where post_type = 'place' and post_parent = $cities order by post_title asc
DISTINCT
将从表中返回唯一的ID's
。
答案 1 :(得分:0)
如果不在array()
中的变量首先将它们放入数组中。并使用array_unique($town);
($ town基于您的数组变量)
array_unique()
将确保数组中的项目将返回没有重复值的新数组。