Question

  <input type="text" name="subcat[0]">
   <input type="text" name="subcat[1]">
   <input type="text" name="subcat[2]">
   <input type="text" name="subcat[3]">

这些是我的模特：

在类别模型

中

public function subcategories()
{
    return $this->hasMany('App\SubCategory','subcategories_id');
}

子类别模型

public function category()
{
    return $this->belongsTo('App\Category' ,'categories_id');
}

控制器

$s = Input::get('subcat');
$input = request('category');
$id = Category::where('CategoryName', $input)->pluck('id');

$subcat = [];



         $category=Category::find($id );


    foreach ($s as $item ) {
    $item->category()->associate($category); 
    $item->save();
    }

我收到错误＆＃34;在字符串上调用成员函数category（）：＆＃34;

Answer 1

$item是您输入的字符串（我猜它必须是子类别的名称）。您应该首先创建子类别。

我认为你应该替换：

foreach ($s as $item ) {
    $item->category()->associate($category); 
    $item->save();
}

人：

foreach ($s as $item) {

    // Get sub category by name or create a new subcategory

    $sub_cat = SubCategory::where('SubCategoryName', $item)->first();

    if (!$sub_cat) {
        $sub_cat = new \App\SubCategory();
        $sub_cat-> SubCategoryName = $item; // <-- replace "SubCategoryName" by 
                                            //     the property you need
                                            //     to update from input

        $sub_cat->save();
    }        
    $category->subcategories()->save($sub_cat);
}

Answer 2

$s是字符串数组。你的for循环可以写成

foreach ($s as $item ) {
    $sub = SubCategory::where('SubCategoryName', $item)->first();
    $sub->category()->associate($category); 
    $sub->save();
}

Laravel 5.4将一组输入保存到belongssto模型

2 个答案: