查找表或视图的依赖对象

时间:2010-12-16 16:21:39

标签: postgresql metadata

背景

在PostgreSQL中删除(或替换)对象时,如果存在依赖关系,则删除将失败(未指定CASCADE)。

问题

数据库返回的错误消息未列出依赖对象。

示例解决方案

查询可能类似于:

SELECT * FROM information_schema i, pg_depend pd WHERE
  i.object_id = pd.object_id AND
  i.object_type = 'TABLE' AND
  i.object_schema = 'public' AND
  i.object_name = 'table_with_dependents';

objid缺失。

相关

问题

如何按名称和类型生成依赖对象列表?

6 个答案:

答案 0 :(得分:17)

简单的方法是:

begin;
drop object cascade;
rollback;

答案 1 :(得分:9)

\d+ your_table

获取受抚养人名单。正如Scott在评论中提到的那样,您可以使用命令行psql和-E选项获取创建的查询,然后使用与上面相同的命令(查看手册)。这样,postgres将打印查询

$ psql -U username -E -c '\d+ table' database

输出相当长,所以一定要将输出传输到文件中。

答案 2 :(得分:9)

对于PostgreSQL 9.3以上,使用以下视图和函数来显示任何用户对象依赖项。我还更新了https://wiki.postgresql.org/wiki/Pg_depend_display

/**** Usage Examples ****
-- Examine the entire object hierarchy
SELECT report.dependency_tree('');

-- Dependencies for any relations with names containing match (in regular expression)
SELECT report.dependency_tree('match');

-- Dependencies for relations person & address
SELECT report.dependency_tree('{person,address}'::text[]);

-- Dependencies for function slice
SELECT report.dependency_tree(ARRAY['slice'::regproc]);

-- Dependencies for type hstore
SELECT report.dependency_tree(ARRAY['hstore'::regtype]);

-- Dependencies for triggers by the name updated
SELECT report.dependency_tree(ARRAY(
  SELECT oid FROM pg_trigger WHERE tgname ~ 'updated'
  ));

-- Dependencies for foreign key constraint names starting with product
SELECT report.dependency_tree(ARRAY(
  SELECT oid FROM pg_constraint
  WHERE conname ~ '^product.*_fk'
  ));
*/

DROP VIEW IF EXISTS report.dependency;
CREATE OR REPLACE VIEW report.dependency AS
WITH RECURSIVE preference AS (
  SELECT 10 AS max_depth
    , 16384 AS min_oid -- user objects only
    , '^(londiste|pgq|pg_toast)'::text AS schema_exclusion
    , '^pg_(conversion|language|ts_(dict|template))'::text AS class_exclusion
    , '{"SCHEMA":"00", "TABLE":"01", "TABLE CONSTRAINT":"02", "DEFAULT VALUE":"03",
        "INDEX":"05", "SEQUENCE":"06", "TRIGGER":"07", "FUNCTION":"08",
        "VIEW":"10", "MATERIALIZED VIEW":"11", "FOREIGN TABLE":"12"}'::json AS type_sort_orders
)
, dependency_pair AS (
    SELECT objid
      , array_agg(objsubid ORDER BY objsubid) AS objsubids
      , upper(obj.type) AS object_type
      , coalesce(obj.schema, substring(obj.identity, E'(\\w+?)\\.'), '') AS object_schema
      , obj.name AS object_name
      , obj.identity AS object_identity
      , refobjid
      , array_agg(refobjsubid ORDER BY refobjsubid) AS refobjsubids
      , upper(refobj.type) AS refobj_type
      , coalesce(CASE WHEN refobj.type='schema' THEN refobj.identity
                                                ELSE refobj.schema END
          , substring(refobj.identity, E'(\\w+?)\\.'), '') AS refobj_schema
      , refobj.name AS refobj_name
      , refobj.identity AS refobj_identity
      , CASE deptype
            WHEN 'n' THEN 'normal'
            WHEN 'a' THEN 'automatic'
            WHEN 'i' THEN 'internal'
            WHEN 'e' THEN 'extension'
            WHEN 'p' THEN 'pinned'
        END AS dependency_type
    FROM pg_depend dep
      , LATERAL pg_identify_object(classid, objid, 0) AS obj
      , LATERAL pg_identify_object(refclassid, refobjid, 0) AS refobj
      , preference
    WHERE deptype = ANY('{n,a}')
    AND objid >= preference.min_oid
    AND (refobjid >= preference.min_oid OR refobjid = 2200) -- need public schema as root node
    AND coalesce(obj.schema, substring(obj.identity, E'(\\w+?)\\.'), '') !~ preference.schema_exclusion
    AND coalesce(CASE WHEN refobj.type='schema' THEN refobj.identity
                                                ELSE refobj.schema END
          , substring(refobj.identity, E'(\\w+?)\\.'), '') !~ preference.schema_exclusion
    GROUP BY objid, obj.type, obj.schema, obj.name, obj.identity
      , refobjid, refobj.type, refobj.schema, refobj.name, refobj.identity, deptype
)
, dependency_hierarchy AS (
    SELECT DISTINCT
        0 AS level,
        refobjid AS objid,
        refobj_type AS object_type,
        refobj_identity AS object_identity,
        --refobjsubids AS objsubids,
        NULL::text AS dependency_type,
        ARRAY[refobjid] AS dependency_chain,
        ARRAY[concat(preference.type_sort_orders->>refobj_type,refobj_type,':',refobj_identity)] AS dependency_sort_chain
    FROM dependency_pair root
    , preference
    WHERE NOT EXISTS
       (SELECT 'x' FROM dependency_pair branch WHERE branch.objid = root.refobjid)
    AND refobj_schema !~ preference.schema_exclusion
    UNION ALL
    SELECT
        level + 1 AS level,
        child.objid,
        child.object_type,
        child.object_identity,
        --child.objsubids,
        child.dependency_type,
        parent.dependency_chain || child.objid,
        parent.dependency_sort_chain || concat(preference.type_sort_orders->>child.object_type,child.object_type,':',child.object_identity)
    FROM dependency_pair child
    JOIN dependency_hierarchy parent ON (parent.objid = child.refobjid)
    , preference
    WHERE level < preference.max_depth
    AND child.object_schema !~ preference.schema_exclusion
    AND child.refobj_schema !~ preference.schema_exclusion
    AND NOT (child.objid = ANY(parent.dependency_chain)) -- prevent circular referencing
)
SELECT * FROM dependency_hierarchy
ORDER BY dependency_chain ;

-- Procedure to report depedency tree using regexp search pattern (relation-only)
CREATE OR REPLACE FUNCTION report.dependency_tree(search_pattern text)
  RETURNS TABLE(dependency_tree text)
  SECURITY DEFINER LANGUAGE SQL
  AS $function$
WITH target AS (
  SELECT objid, dependency_chain
  FROM report.dependency
  WHERE object_identity ~ search_pattern
)
, list AS (
  SELECT
    format('%*s%s %s', -4*level
          , CASE WHEN object_identity ~ search_pattern THEN '*' END
          , object_type, object_identity
    ) AS dependency_tree
  , dependency_sort_chain
  FROM target
  JOIN report.dependency report
    ON report.objid = ANY(target.dependency_chain) -- root-bound chain
    OR target.objid = ANY(report.dependency_chain) -- leaf-bound chain
  WHERE length(search_pattern) > 0
  -- Do NOT waste search time on blank/null search_pattern.
  UNION
  -- Query the entire dependencies instead.
  SELECT
    format('%*s%s %s', 4*level, '', object_type, object_identity) AS depedency_tree
  , dependency_sort_chain
  FROM report.dependency
  WHERE length(coalesce(search_pattern,'')) = 0
)
SELECT dependency_tree FROM list
ORDER BY dependency_sort_chain;
$function$ ;

-- Procedure to report depedency tree by specific relation name(s) (in text array)
CREATE OR REPLACE FUNCTION report.dependency_tree(object_names text[])
  RETURNS TABLE(dependency_tree text)
  SECURITY DEFINER LANGUAGE SQL
  AS $function$
WITH target AS (
  SELECT objid, dependency_chain
  FROM report.dependency
  JOIN unnest(object_names) AS target(objname) ON objid = objname::regclass
)
, list AS (
  SELECT DISTINCT
    format('%*s%s %s', -4*level
          , CASE WHEN object_identity = ANY(object_names) THEN '*' END
          , object_type, object_identity
    ) AS dependency_tree
  , dependency_sort_chain
  FROM target
  JOIN report.dependency report
    ON report.objid = ANY(target.dependency_chain) -- root-bound chain
    OR target.objid = ANY(report.dependency_chain) -- leaf-bound chain
)
SELECT dependency_tree FROM list
ORDER BY dependency_sort_chain;
$function$ ;

-- Procedure to report depedency tree by oid
CREATE OR REPLACE FUNCTION report.dependency_tree(object_ids oid[])
  RETURNS TABLE(dependency_tree text)
  SECURITY DEFINER LANGUAGE SQL
  AS $function$
WITH target AS (
  SELECT objid, dependency_chain
  FROM report.dependency
  JOIN unnest(object_ids) AS target(objid) USING (objid)
)
, list AS (
  SELECT DISTINCT
    format('%*s%s %s', -4*level
          , CASE WHEN report.objid = ANY(object_ids) THEN '*' END
          , object_type, object_identity
    ) AS dependency_tree
  , dependency_sort_chain
  FROM target
  JOIN report.dependency report
    ON report.objid = ANY(target.dependency_chain) -- root-bound chain
    OR target.objid = ANY(report.dependency_chain) -- leaf-bound chain
)
SELECT dependency_tree FROM list
ORDER BY dependency_sort_chain;
$function$ ;

答案 3 :(得分:4)

在查询中包含嵌套视图,如下所示:

WITH RECURSIVE view_deps AS (
SELECT DISTINCT dependent_ns.nspname as dependent_schema
, dependent_view.relname as dependent_view
, source_ns.nspname as source_schema
, source_table.relname as source_table
FROM pg_depend
JOIN pg_rewrite ON pg_depend.objid = pg_rewrite.oid
JOIN pg_class as dependent_view ON pg_rewrite.ev_class = dependent_view.oid
JOIN pg_class as source_table ON pg_depend.refobjid = source_table.oid
JOIN pg_namespace dependent_ns ON dependent_ns.oid = dependent_view.relnamespace
JOIN pg_namespace source_ns ON source_ns.oid = source_table.relnamespace
WHERE NOT (dependent_ns.nspname = source_ns.nspname AND dependent_view.relname = source_table.relname)
UNION
SELECT DISTINCT dependent_ns.nspname as dependent_schema
, dependent_view.relname as dependent_view
, source_ns.nspname as source_schema
, source_table.relname as source_table
FROM pg_depend
JOIN pg_rewrite ON pg_depend.objid = pg_rewrite.oid
JOIN pg_class as dependent_view ON pg_rewrite.ev_class = dependent_view.oid
JOIN pg_class as source_table ON pg_depend.refobjid = source_table.oid
JOIN pg_namespace dependent_ns ON dependent_ns.oid = dependent_view.relnamespace
JOIN pg_namespace source_ns ON source_ns.oid = source_table.relnamespace
INNER JOIN view_deps vd
    ON vd.dependent_schema = source_ns.nspname
    AND vd.dependent_view = source_table.relname
    AND NOT (dependent_ns.nspname = vd.dependent_schema AND dependent_view.relname = vd.dependent_view)
)

SELECT *
FROM view_deps
ORDER BY source_schema, source_table;

如果您关心特定的表属性,请将其添加到递归CTE的顶部:

JOIN pg_attribute ON pg_depend.refobjid = pg_attribute.attrelid 
    AND pg_depend.refobjsubid = pg_attribute.attnum 
...
WHERE 
source_ns.nspname = 'my_schema'
AND source_table.relname = 'my_table'
AND pg_attribute.attnum > 0 
AND pg_attribute.attname = 'my_column'

答案 4 :(得分:0)

pg_constraint包含数据库中的所有约束,您可以使用所有外键约束中的oidconfrelid列出conrelid从属表

查询看起来像这样

select confrelid,conrelid from pg_constraint where contype='f';

答案 5 :(得分:0)

非常简单而简短的查询:

SELECT * FROM INFORMATION_SCHEMA.VIEW_COLUMN_USAGE WHERE COLUMN_NAME = 'column_name' and table_name = 'table_name'