我想删除大字符串(不是文件)中的空行。 这是字符串:
The unique begin of a line in my string, after that a content same endline
The unique begin of a line in my string, after that a content same endline
The unique begin of a line in my string, after that a content same endline
这就是它在记事本++上的显示方式:
答案 0 :(得分:3)
使用正则表达式。点击regex reference链接可以帮助您入门。或者更好regex_replace。
您的正则表达式将如下所示
/\n\s*\n/
对于正则表达式测试,在线regex tester可能会有所帮助。
#include <iostream>
#include <string>
#include <regex>
int main ()
{
std::string s ("there is a line \n \nanother line\n \nand last one in the string\n");
std::regex e ("\\n\\s*\\n");
std::cout << std::regex_replace (s,e,"\n");
return 0;
}
答案 1 :(得分:0)
解决方案:
string myString = "The string which contains double \r\n \r\n so it will be removed with this algorithm.";
int myIndex = 0;
while (myIndex < myString.length()) {
if (myString[myIndex] == '\n') {
myIndex++;
while (myIndex < myString.length() && (myString[myIndex] == ' ' || myString[myIndex] == '\t' || myString[myIndex] == '\r' || myString[myIndex] == '\n')) {
myString.erase(myIndex, 1);
}
} else {
myIndex++;
}
}