Question

我有一个字符串：

Hello“引用字符串”和“棘手”的东西'世界

并希望获取字符串减去引用的部分。如，

Hello and world

有什么建议吗？

Answer 1

resultString = Regex.Replace(subjectString, 
    @"([""'])# Match a quote, remember which one
    (?:      # Then...
     (?!\1)  # (as long as the next character is not the same quote as before)
     .       # match any character
    )*       # any number of times
    \1       # until the corresponding closing quote
    \s*      # plus optional whitespace
    ", 
    "", RegexOptions.IgnorePatternWhitespace);

将适用于您的示例。

resultString = Regex.Replace(subjectString, 
    @"([""'])# Match a quote, remember which one
    (?:      # Then...
     (?!\1)  # (as long as the next character is not the same quote as before)
     \\?.    # match any escaped or unescaped character
    )*       # any number of times
    \1       # until the corresponding closing quote
    \s*      # plus optional whitespace
    ", 
    "", RegexOptions.IgnorePatternWhitespace);

也会处理转义报价。

所以它会正确转换

Hello "quoted \"string\\" and 'tricky"stuff' world

进入

Hello and world

Answer 2

使用正则表达式将任何带引号的字符串与字符串匹配，并将其替换为空字符串。使用Regex.Replace()方法进行模式匹配和替换。

Answer 3

如果像我一样，你害怕正则表达式，我会根据你的示例字符串整理一个功能性的方法。可能有一种方法可以缩短代码，但我还没有找到它。

private static string RemoveQuotes(IEnumerable<char> input)
{
    string part = new string(input.TakeWhile(c => c != '"' && c != '\'').ToArray());
    var rest = input.SkipWhile(c => c != '"' && c != '\'');
    if(string.IsNullOrEmpty(new string(rest.ToArray())))
        return part;
    char delim = rest.First();
    var afterIgnore = rest.Skip(1).SkipWhile(c => c != delim).Skip(1);
    StringBuilder full = new StringBuilder(part);
    return full.Append(RemoveQuotes(afterIgnore)).ToString();
}

如何从C＃中的字符串中删除带引号的字符串文字？

3 个答案: