我在索引中有两个dropDownlist,当我选择提交按钮时它将在控制器中获取动作,并执行一些操作并再次使用gridview呈现索引,但是选定的dropDownList变为空白,我该如何设置默认值dropDownllist ??
任何建议都应该值得赞赏...... 这是我的观点
<div class="col-sm-12" align="center">
<?= $form->field($model, 'fk_int_payroll_month')->dropDownList(
ArrayHelper::map(TblPayrollMonth::find()->all(), 'pk_int_payroll_month_id','vchr_month'),
['prompt'=> 'Select...'])
?>
</div>
<div class="col-sm-12" align="center">
<?= $form->field($model, 'fk_int_payroll_year')->dropDownList(
ArrayHelper::map(TblPayrollYear::find()->all(), 'pk_int_payroll_year_id','year'),
['options' => [isset($_POST['fk_int_payroll_year'])?'fk_int_payroll_year':'' => ['Selected'=>true]]],
['prompt'=> 'Seect...'])
?>
</div>
这是我的控制器
public function actionDisplay()
{
$model = new TblPayroll();
if(Yii::$app->request->post()!=null)
{
$data = Yii::$app->request->post();
// var_dump($data);
// die;
$month = $data['TblPayroll']['fk_int_payroll_month'];
$year = $data['TblPayroll']['fk_int_payroll_year'];
/* Be careful with this! */
$dataProviderSearch = new ActiveDataProvider
([
'query' => TblPayroll::find()->where(['fk_int_payroll_month'=>$month, 'fk_int_payroll_year'=> $year]),
'pagination' => ['pageSize' => 5],
]);
if($dataProviderSearch)
{
return $this->render('index', [
'dataProviderSearch' => $dataProviderSearch,
'model' => $model,
]);
}
}
else{
return $this->render('index', ['model' => $model]);
}
当我选择下拉列表时,它将gott actionDisplay,并找到dataprovider,然后再次渲染到索引,那么我该如何在dropDownlist中显示默认选择值?
答案 0 :(得分:1)
如果您使用的是activeRecord,那么在controllerAction中,您应该为$ model-&gt; your_fiedl指定默认值所需的值
else{
$model->fk_int_payroll_month = 3
return $this->render('index', ['model' => $model]);
}
如果您没有使用活动记录,则可以使用
->dropDownList($yourlist ,$selection)
例如
->dropDownList(ArrayHelper::map(TblPayrollMonth::find()->all() ,3)