Question

在ASP.NET MVC中进行分页的最优选和最简单的方法是什么？即什么是将列表拆分成几个可浏览页面的最简单方法。

举一个例子，我想从数据库/网关/存储库中获取一个元素列表，如下所示：

public ActionResult ListMyItems()
{
    List<Item> list = ItemDB.GetListOfItems();
    ViewData["ItemList"] = list;

    return View();
}

为简单起见，我想为我的操作指定一个页码作为参数。像这样：

public ActionResult ListMyItems(int page)
{
   //...
}

Answer 1

那么，数据源是什么？你的行为可以采取一些默认的论点，即

ActionResult Search(string query, int startIndex, int pageSize) {...}

默认路由设置，以便startIndex为0而pageSize为（比方说）20：

        routes.MapRoute("Search", "Search/{query}/{startIndex}",
                        new
                        {
                            controller = "Home", action = "Search",
                            startIndex = 0, pageSize = 20
                        });

要拆分Feed，您可以非常轻松地使用LINQ：

var page = source.Skip(startIndex).Take(pageSize);

（或者如果使用“pageNumber”而不是“startIndex”，则进行乘法运算）

使用LINQ-toSQL，EF等 - 这也应该“组合”到数据库。

然后您应该能够使用动作链接到下一页（等）：

<%=Html.ActionLink("next page", "Search", new {
                query, startIndex = startIndex + pageSize, pageSize }) %>

Answer 2

我遇到了同样的问题，并从

中找到了一个非常优雅的Pager Class解决方案

http://blogs.taiga.nl/martijn/2008/08/27/paging-with-aspnet-mvc/

在您的控制器中，通话看起来像：

return View(partnerList.ToPagedList(currentPageIndex, pageSize));

并在您看来：

<div class="pager">
    Seite: <%= Html.Pager(ViewData.Model.PageSize, 
                          ViewData.Model.PageNumber,
                          ViewData.Model.TotalItemCount)%>
</div>

Answer 3

我想用前端介绍一种简单的方法：

<强>控制器：

public ActionResult Index(int page = 0)
{
    const int PageSize = 3; // you can always do something more elegant to set this

    var count = this.dataSource.Count();

    var data = this.dataSource.Skip(page * PageSize).Take(PageSize).ToList();

    this.ViewBag.MaxPage = (count / PageSize) - (count % PageSize == 0 ? 1 : 0);

    this.ViewBag.Page = page;

    return this.View(data);
}

查看：

@* rest of file with view *@ @if (ViewBag.Page > 0) { <a href="@Url.Action("Index", new { page = ViewBag.Page - 1 })" class="btn btn-default"> « Prev </a> } @if (ViewBag.Page < ViewBag.MaxPage) { <a href="@Url.Action("Index", new { page = ViewBag.Page + 1 })" class="btn btn-default"> Next » </a> }

Answer 4

控制器

  public List<Match> GetMatchCore(int page, int pageSize, out int totalRecord, out int totalPage)
    {
        SignalRDataContext db = new SignalRDataContext();
        var query = new List<Match>();
        totalRecord = db.Matches.Count();
        totalPage = (totalRecord / pageSize) + ((totalRecord % pageSize) > 0 ? 1 : 0);
        query = db.Matches.OrderBy(a => a.QuestionID).Skip(((page - 1) * pageSize)).Take(pageSize).ToList();
        return query;
    }

BusinessLogic

 if (ViewBag.dbCount != null)
    {
        for (int i = 1; i <= ViewBag.dbCount; i++)
        {
            <ul class="pagination">
                <li>@Html.ActionLink(@i.ToString(), "Index", "Grid", new { page = @i },null)</li> 
            </ul>
        }
    }

查看显示总页数

mysql> CREATE TABLE prime2 LIKE prime;
Query OK, 0 rows affected (0.08 sec)

mysql> SELECT LAST_INSERT_ID(); //From table prime!!!
+------------------+
| LAST_INSERT_ID() |
+------------------+
|                3 |
+------------------+
1 row in set (0.00 sec)


mysql> INSERT INTO prime2 VALUES(1,1);
Query OK, 1 row affected (0.01 sec)

mysql> SELECT LAST_INSERT_ID(); 
+------------------+
| LAST_INSERT_ID() |
+------------------+
|                3 |
+------------------+
1 row in set (0.00 sec) //From table prime!!!

Answer 5

我认为在ASP.NET MVC应用程序中创建分页的最简单方法是使用PagedList库。

以下github存储库中有一个完整的示例。希望它会有所帮助。

// Method descriptor #11 ()Ljava/lang/Object;
// Stack: 5, Locals: 1
public java.lang.Object invoke();
   0  getstatic user$eval16141$fn__16142.const__0 : clojure.lang.Var [15]
   3  invokevirtual clojure.lang.Var.getRawRoot() : java.lang.Object [20]
   6  checkcast clojure.lang.IFn [22]
   9  ldc <String "%08x"> [24]
  11  ldc2_w <Long 4063516280> [25]
  14  l2i
  15  ldc2_w <Long 4> [27]
  18  invokestatic clojure.lang.RT.intCast(long) : int [34]
  21  invokestatic clojure.lang.Numbers.unsignedShiftRightInt(int, int) : int [40]
  24  invokestatic java.lang.Integer.valueOf(int) : java.lang.Integer [46]
  27  invokeinterface clojure.lang.IFn.invoke(java.lang.Object, java.lang.Object) : java.lang.Object [49] [nargs: 3]
  32  areturn
    Line numbers:
      [pc: 0, line: 1]
      [pc: 6, line: 1]
      [pc: 14, line: 1]
      [pc: 21, line: 1]
      [pc: 27, line: 1]
    Local variable table:
      [pc: 0, pc: 32] local: this index: 0 type: java.lang.Object

演示链接：http://ajaxpagination.azurewebsites.net/

源代码：https://github.com/ungleng/SimpleAjaxPagedListAndSearchMVC5

Answer 6

实体

public class PageEntity
{
    public int Page { get; set; }
    public string Class { get; set; }
}

public class Pagination
{
    public List<PageEntity> Pages { get; set; }
    public int Next { get; set; }
    public int Previous { get; set; }
    public string NextClass { get; set; }
    public string PreviousClass { get; set; }
    public bool Display { get; set; }
    public string Query { get; set; }
}

HTML

<nav>
    <div class="navigation" style="text-align: center">
        <ul class="pagination">
            <li class="page-item @Model.NextClass"><a class="page-link" href="?page=@(@Model.Previous+@Model.Query)">&laquo;</a></li>
            @foreach (var item in @Model.Pages)
            {
                <li class="page-item @item.Class"><a class="page-link" href="?page=@(item.Page+@Model.Query)">@item.Page</a></li>
            }
            <li class="page-item @Model.NextClass"><a class="page-link" href="?page=@(@Model.Next+@Model.Query)">&raquo;</a></li>
        </ul>
    </div>
 </nav>

寻呼逻辑

public Pagination GetCategoryPaging(int currentPage, int recordCount, string query)
{
    string pageClass = string.Empty; int pageSize = 10, innerCount = 5;

    Pagination pagination = new Pagination();
    pagination.Pages = new List<PageEntity>();
    pagination.Next = currentPage + 1;
    pagination.Previous = ((currentPage - 1) > 0) ? (currentPage - 1) : 1;
    pagination.Query = query;

    int totalPages = ((int)recordCount % pageSize) == 0 ? (int)recordCount / pageSize : (int)recordCount / pageSize + 1;

    int loopStart = 1, loopCount = 1;

    if ((currentPage - 2) > 0)
    {
        loopStart = (currentPage - 2);
    }

    for (int i = loopStart; i <= totalPages; i++)
    {
        pagination.Pages.Add(new PageEntity { Page = i, Class = string.Empty });

        if (loopCount == innerCount)
        { break; }

        loopCount++;
    }

    if (totalPages <= innerCount)
    {
        pagination.PreviousClass = "disabled";
    }

    foreach (var item in pagination.Pages.Where(x => x.Page == currentPage))
    {
        item.Class = "active";
    }

    if (pagination.Pages.Count() <= 1)
    {
        pagination.Display = false;
    }

    return pagination;
}

使用控制器

public ActionResult GetPages()
{
    int currentPage = 1; string search = string.Empty;
    if (!string.IsNullOrEmpty(Request.QueryString["page"]))
    {
        currentPage = Convert.ToInt32(Request.QueryString["page"]);
    }

    if (!string.IsNullOrEmpty(Request.QueryString["q"]))
    {
        search = "&q=" + Request.QueryString["q"];
    }
    /* to be Fetched from database using count */
    int recordCount = 100;

    Place place = new Place();
    Pagination pagination = place.GetCategoryPaging(currentPage, recordCount, search);

    return PartialView("Controls/_Pagination", pagination);
}

Answer 7

public ActionResult Paging(int? pageno,bool? fwd,bool? bwd)        
{
    if(pageno!=null)
     {
       Session["currentpage"] = pageno;
     }

    using (HatronEntities DB = new HatronEntities())
    {
        if(fwd!=null && (bool)fwd)
        {
            pageno = Convert.ToInt32(Session["currentpage"]) + 1;
            Session["currentpage"] = pageno;
        }
        if (bwd != null && (bool)bwd)
        {
            pageno = Convert.ToInt32(Session["currentpage"]) - 1;
            Session["currentpage"] = pageno;
        }
        if (pageno==null)
        {
            pageno = 1;
        }
        if(pageno<0)
        {
            pageno = 1;
        }
        int total = DB.EmployeePromotion(0, 0, 0).Count();
        int  totalPage = (int)Math.Ceiling((double)total / 20);
        ViewBag.pages = totalPage;
        if (pageno > totalPage)
        {
            pageno = totalPage;
        }
        return View (DB.EmployeePromotion(0,0,0).Skip(GetSkip((int)pageno,20)).Take(20).ToList());     
    }
}

private static int GetSkip(int pageIndex, int take)
{
    return (pageIndex - 1) * take;
}

@model IEnumerable<EmployeePromotion_Result>
@{
  Layout = null;
}

 <!DOCTYPE html>

 <html>
 <head>
    <meta name="viewport" content="width=device-width" />
    <title>Paging</title>
  </head>
  <body>
 <div> 
    <table border="1">
        @foreach (var itm in Model)
        {
 <tr>
   <td>@itm.District</td>
   <td>@itm.employee</td>
   <td>@itm.PromotionTo</td>
 </tr>
        }
    </table>
    <a href="@Url.Action("Paging", "Home",new { pageno=1 })">First  page</a> 
    <a href="@Url.Action("Paging", "Home", new { bwd =true })"><<</a> 
    @for(int itmp =1; itmp< Convert.ToInt32(ViewBag.pages)+1;itmp++)
   {
       <a href="@Url.Action("Paging", "Home",new { pageno=itmp   })">@itmp.ToString()</a>
   }
    <a href="@Url.Action("Paging", "Home", new { fwd = true })">>></a> 
    <a href="@Url.Action("Paging", "Home", new { pageno =                                                                               Convert.ToInt32(ViewBag.pages) })">Last page</a> 
</div>
   </body>
  </html>

Answer 8

a link在这里帮助了我。

它使用PagedList.MVC NuGet包。我将尝试总结步骤

安装PagedList.MVC NuGet软件包
构建项目
添加 using PagedList; 到控制器
修改您的操作以设置页面 public ActionResult ListMyItems(int? page) { List list = ItemDB.GetListOfItems(); int pageSize = 3; int pageNumber = (page ?? 1); return View(list.ToPagedList(pageNumber, pageSize)); }
在页面底部添加分页链接 @*Your existing view*@ Page @(Model.PageCount < Model.PageNumber ? 0 : Model.PageNumber) of @Model.PageCount @Html.PagedListPager(Model, page => Url.Action("Index", new { page, sortOrder = ViewBag.CurrentSort, currentFilter = ViewBag.CurrentFilter }))

我如何在ASP.NET MVC中进行分页？

8 个答案: