我目前正在开发一个针对补丁c函数调用的演示，想法是你有一个共享的c文件（例如：from random import *
def doorPriceRandomizer():
door1 = randint(0,2) #If a door is defined 0, it has a price in it
door2 = randint(0,2) #If a door is defined either 1 or 2, it has a goat in it.
door3 = randint(0,2)
while door2 == door1:
door2 = randint(0,2)
while door3 == door2 or door3 == door1:
door3 = randint(0,2)
return door1,door2,door3 #This random placement generator seems to be working fine.
while True:
loopStart = 0
amountWin = 0
amountLose = 0
try:
loopEnd = int(input("How often would you like to run this simulation: "))
if loopEnd < 0:
raise ValueError
doorChangeUser = int(input("[0] = Do not change door; [1] = Change door: "))
if doorChangeUser not in range(0,2):
raise ValueError
except ValueError:
print("Invalid input. Try again.\n")
else:
while loopStart != loopEnd:
gameDoors = doorPriceRandomizer()
inputUser = randint(0,2)
if doorChangeUser == 0:
if gameDoors[inputUser] == 0:
amountWin += 1
loopStart += 1
else:
amountLose += 1
loopStart += 1
elif doorChangeUser == 1:
ChangeRandom = 0
while gameDoors[ChangeRandom] == gameDoors[inputUser]:
ChangeRandom = randint(0,2)
if gameDoors[ChangeRandom] == 0:
amountWin += 1
loopStart += 1
else:
amountLose += 1
loopStart += 1
print("Win amount: ",amountWin,"\tLose amount: ",amountLose)
），它有一个名为{{1}的导出函数}在头文件lib.c中。
目前我正在尝试执行以下操作：
void foo()然而，这给了我以下错误：
lib.h有谁知道如何解决这个问题？感谢
答案 0 :(得分：2)
这一行：
foo = &foo_patch;
不是重新分配函数指针，而是尝试重新分配函数foo本身的地址，这是不允许的，因为它是r-value。
如果要重新指定指针foo_original以指向foo_patch，则会得到无限递归循环，因为foo_patch会调用{{1}指向的函数}}