Question

请问有人可以告诉我以下问题：我需要解决以下SQL查询。该数据库是Oracle 11g。

Select 
    article_cd, dc_cd, 
    nvl(soh_to_dmp - least(soh_to_dmp, nvl(sum(adj_alc_tot_frcst), 0)) ,0) v_dump_qty,
    used_by_date 
from 
    inventory

我附上了截图，以表格格式显示数据

please refer to this screenshot

我想要一个专栏＆＃34; shirink＆＃34;这给了＆＃34; dump qty - sum（所有先前收缩）和如果dump qty - sum（所有先前收缩）＆lt; 0然后0如上图所示收缩为777 = 0表示0 =（0-777）= -777这应该为2548 = 0（2548 - 777）= 1771 = 8356 =（8356 - （777 + 1771））= 5808

我尝试使用滞后功能：

v_dump qty- lag ( v_dump qty) over ( partition by article_code,dc_code) order by ( article_code, dc code, used_date)

但它无效

Answer 1

以下查询可能为解决您的问题提供了一个起点。我们现在没有很多测试数据。但是，当我们使用＆＃34;库存＆＃34;表，填写测试数据，如下所示：

create table inventory(
  iid number primary key
, usebydate date
, qty number
);
-- select * from inventory
IID USEBYDATE   QTY
1   30-AUG-2017 0
2   31-AUG-2017 0
3   30-SEP-2017 777
4   30-OCT-2017 0
5   01-NOV-2017 0
6   16-NOV-2017 0
7   30-NOV-2017 0
8   01-JAN-2018 0
9   31-JAN-2018 2548
10  28-FEB-2018 8356

...可以看出，包含自联接，结合CASE和＆＃34;窗口＆＃34;的查询可能会提供您需要的结果。

select 
  i.iid
, i.qty 
, case 
    when ( i.qty - ( sum(i2.shrink) over ( order by i.iid rows between unbounded preceding and 1 preceding) ) ) < 0 
      or ( i.qty - ( sum(i2.shrink) over ( order by i.iid rows between unbounded preceding and 1 preceding) ) ) is null
      then 0
    else ( i.qty - ( sum(i2.shrink) over ( order by i.iid rows between unbounded preceding and 1 preceding) ) )
  end shrink 
from inventory i join 
  ( select 
      iid
    , case 
        when ( qty - ( sum(qty) 
          over ( order by iid rows between unbounded preceding and 1 preceding ) ) ) < 0 then 0
        else ( qty - ( sum(qty) 
              over ( order by iid rows between unbounded preceding and 1 preceding) ) )
       end shrink
       from inventory
   ) i2
   on i.iid = i2.iid
order by i.iid
;

输出：

IID QTY     SHRINK
1   0       0
2   0       0
3   777     777
4   0       0
5   0       0
6   0       0
7   0       0
8   0       0
9   2548    1771
10  8356    5808

相同的查询，使用＆＃34; usebydate＆＃34;在ON子句中，给我们：

-- -----------------------------------------------------------------------------
--  on clause with date instead of iid
-- -----------------------------------------------------------------------------
select 
  i.usebydate
, i.qty 
, case 
    when ( i.qty - ( sum(i2.shrink) over ( order by i.usebydate rows between unbounded preceding and 1 preceding) ) ) < 0 
      or ( i.qty - ( sum(i2.shrink) over ( order by i.usebydate rows between unbounded preceding and 1 preceding) ) ) is null
      then 0
    else ( i.qty - ( sum(i2.shrink) over ( order by i.usebydate rows between unbounded preceding and 1 preceding) ) )
  end shrink 
from inventory i join 
  ( select 
      usebydate
    , case 
        when ( qty - ( sum(qty) 
          over ( order by usebydate rows between unbounded preceding and 1 preceding ) ) ) < 0 then 0
        else ( qty - ( sum(qty) 
              over ( order by usebydate rows between unbounded preceding and 1 preceding) ) )
       end shrink
       from inventory
   ) i2
   on i.usebydate = i2.usebydate
order by i.usebydate
;

-- output
    USEBYDATE   QTY     SHRINK
    30-AUG-2017 0       0
    31-AUG-2017 0       0
    30-SEP-2017 777     777
    30-OCT-2017 0       0
    01-NOV-2017 0       0
    16-NOV-2017 0       0
    30-NOV-2017 0       0
    01-JAN-2018 0       0
    31-JAN-2018 2548    1771
    28-FEB-2018 8356    5808

我确定可以修改/简化。此外，它还需要彻底的测试。适用于：Oracle 12c，Oracle 11g R2。 dbfiddle here

SQL查询 - 在形成sql查询时需要帮助

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