我只是想知道也许你可以帮助我解决我的问题。 我有一个带有多个模块的Maven项目。 不幸的是,我无法从另一个模块导入(不能使用来自另一个xsd的类型)XSD。
我的项目结构如下:
我有两个模块,名称是用户管理一般和手稿管理一般。
用户管理常规包含名称为 user.management.bean.xsd 的XSD。我想将此XSD导入到 manuscript.management.bean.xsd 中,该 manuscript.management.bean.xsd 位于我的 manuscript-management-general 模块中。
我尝试了多种可能的解决方案而没有成功。
手稿 - 管理 - 通用模块的POM如下:
<properties>
<user-management-general.version>0.0.1-SNAPSHOT</user-management-general.version>
</properties>
<dependencies>
<dependency>
<groupId>org.jvnet.jaxb2_commons</groupId>
<artifactId>jaxb2-basics-runtime</artifactId>
</dependency>
<dependency>
<groupId>javax.validation</groupId>
<artifactId>validation-api</artifactId>
</dependency>
<dependency>
<groupId>manuscript.module.user.management</groupId>
<artifactId>user-management-general</artifactId>
<version>${user-management-general.version}</version>
</dependency>
</dependencies>
<build>
<plugins>
<plugin>
<groupId>org.jvnet.jaxb2.maven2</groupId>
<artifactId>maven-jaxb2-plugin</artifactId>
</plugin>
</plugins>
</build>
jaxb2插件如下:
<pluginManagement>
<plugins>
<plugin>
<groupId>org.jvnet.jaxb2.maven2</groupId>
<artifactId>maven-jaxb2-plugin</artifactId>
<version>${maven-jaxb2-plugin.version}</version>
<executions>
<execution>
<phase>generate-resources</phase>
<goals>
<goal>generate</goal>
</goals>
<configuration>
<generateDirectory>${project.basedir}/src/generated</generateDirectory>
<extension>true</extension>
<removeOldOutput>true</removeOldOutput>
<useDependenciesAsEpisodes>true</useDependenciesAsEpisodes>
<scanDependenciesForBindings>true</scanDependenciesForBindings>
<args>
<arg>-XtoString</arg>
<!-- <arg>-no-header</arg> -->
<!-- <arg>-XReplacePrimitives</arg> -->
<arg>-XJsr303Annotations</arg>
<!-- <arg>-XJsr303Annotations:targetNamespace=a</arg> -->
<arg>-XhashCode</arg>
<!-- <arg>-Xequals</arg> -->
<arg>-Xsetters</arg>
</args>
<plugins>
<plugin>
<groupId>com.github.krasa</groupId>
<artifactId>krasa-jaxb-tools</artifactId>
<version>${krasa-jaxb-tools.version}</version>
</plugin>
<plugin>
<groupId>org.jvnet.jaxb2_commons</groupId>
<artifactId>jaxb2-basics</artifactId>
<version>${jaxb2-basics.version}</version>
</plugin>
</plugins>
</configuration>
</execution>
</executions>
</plugin>
</plugins>
</pluginManagement>
user.management.bean.xsd是
<xsd:schema xmlns:xsd="http://www.w3.org/2001/XMLSchema"
targetNamespace="http://manuscript/module/user/management/bean"
xmlns="http://manuscript/module/user/management/bean"
elementFormDefault="qualified">
<xsd:complexType name="academicDisciplines">
<xsd:sequence>
<xsd:element name="AcademicDisciplinesId" type="xsd:string" />
<xsd:element name="AcademicDisciplinesName" type="xsd:string" />
</xsd:sequence>
</xsd:complexType>
</xsd:schema>
我想在我的manuscript.management.bean.xsd中使用这个复杂类型作为类型。目前该文件如下:
<xsd:schema xmlns:xsd="http://www.w3.org/2001/XMLSchema"
targetNamespace="http://manuscript/module/manuscript/management/bean"
xmlns="http://manuscript/module/manuscript/management/bean"
xmlns:usermanagement="http://manuscript/module/user/management/bean"
xmlns:jaxb="http://java.sun.com/xml/ns/jaxb"
elementFormDefault="qualified">
<xsd:import namespace="http://manuscript/module/user/management/bean" schemaLocation="???"/>
<xsd:complexType name="submission">
<xsd:sequence>
<xsd:element name="AcademicDisciplines" type="usermanagement:academicDisciplines" minOccurs="1" maxOccurs="unbounded" />
</xsd:sequence>
</xsd:complexType>
<xsd:simpleType name="ROLE">
<xsd:restriction base="xsd:string">
<xsd:enumeration value="AUTHOR_ROLE" />
<xsd:enumeration value="REVIEWER_ROLE" />
<xsd:enumeration value="EDITOR_ROLE" />
<xsd:enumeration value="ADMIN_ROLE" />
</xsd:restriction>
</xsd:simpleType>
<xsd:complexType name="basicResponse">
<xsd:sequence>
<xsd:element name="ExceptionMessage" type="xsd:string" />
<xsd:element name="SuccessMessage" type="xsd:string" />
</xsd:sequence>
</xsd:complexType>
</xsd:schema>
我尝试通过以下方式识别我的xsd,但它不起作用:
<xsd:import namespace="http://manuscript/module/user/management/bean" schemaLocation="maven:manuscript.module.user.management:user-management-general:jar::!/src/main/resources/user.management.bean.xsd" />
GitHub网址:
如果你能帮助我解决这个问题,我将非常感激。 抱歉我的英文:)