Question

这个游戏现在我已经解决了直到最后。但是这里还有一个问题是如何替换字符串中的重复单词？请帮我！谢谢。例如：我的自定义文件里面有单词：“apple”，当用破折号隐藏单词时：“-----”但是当我用破折号替换字符串时我只能用1 p代替破折号：“ap-le”如何用2p代替破折号：“apple”。我以前的帖子为这个程序：How do i detect the repeat input in my hangman game (Python)!。这是我要替换的代码：

def getGuessedWord():
    pos = word.index(guessword.lower())
    print(pos)
    global words             
    words = words[:pos]+ guessword.lower() +words[pos+1:]
    print(words)
    return words

Answer 1

我对过滤猜测字母的整体问题的解决方案是以下一组功能：

guessed_letters = set()
def guess(letter):
    global guessed_letters
    guessed_letters.add(letter)

def filter_letter(letter):
    if letter in guessed_letters:
        return letter
    else:
        return '-'

def filtered(words):
    for word in words:
        output = ''
        for letter in word:
            output += filter_letter(letter)
        yield output

或更紧凑：

guessed_letters = set()
def guess(letter):
    global guessed_letters
    guessed_letters.add(letter)

def filter_letter(letter):
    return letter if letter in guessed_letters else '-'

def filtered(words):
    return [''.join(map(filter_letter, word)) for word in words]

这样：

>>> words = "bubbly water".split()
>>> guess('a')
>>> ' '.join(filtered(words))
'------ -a---'
>>> guess('b')
>>> ' '.join(filtered(words))
'b-bb-- -a---

如何替换python中的重复单词（Hangman Game）！

1 个答案: