Question

嘿伙计们，请你帮我找到这个特殊代码中的任何错误我是php新手我不太了解但是错误是

解析错误：语法错误，意外'$ sql_query'（T_VARIABLE）

<?php

require"init.php";

$user_name = "Nikhil123";
$user_pass = "Sawant"

$sql_query = "select name from user_info where username like '$user_name' and userpass like '$user_pass' ;" ;

$result = mysqli_query($con,$sql_query);

if(mysqli_num_rows($result)>0)
{
    $row = mysqli_fetch_assoc($result);
    $name = $row("name");
    echo "<h3> HELLO welcome".$name "</h3>";
}
else
{
    echo "No INFO";
}

?>

Answer 1

在;之后添加$user_pass = "Sawant"。在.中的$name和"</h3>";之间添加echo "<h3> HELLO welcome".$name "</h3>";：

<?php

require"init.php";

$user_name = "Nikhil123";
$user_pass = "Sawant";

$sql_query = "select name from user_info where username like '$user_name' and userpass like '$user_pass' ;" ;

$result = mysqli_query($con,$sql_query);

if(mysqli_num_rows($result)>0)
{
    $row = mysqli_fetch_assoc($result);
    $name = $row("name");
    echo "<h3> HELLO welcome".$name ."</h3>";
}
else
{
    echo "No INFO";
}

?>

Answer 2

使用单引号代替＆＃34; ...＆＃34;对于sql - 即＆＃39;选择...＆＃34;＆＃39;。$ var。＆＃39;＆＃34; ....＆＃39 ;;

$ sql_query =＆＃39;从user_info中选择名称，其中包含＆＃34;＆＃39;。$ user_name。＆＃39;＆＃34;和userpass类似＆＃34;＆＃39;。$ user_pass。＆＃39;＆＃34; ;＆＃39; ;

语法错误，意外'$ sql_query'（T_VARIABLE）

2 个答案: