Question

我正在尝试创建一个PHP表单，以便在我的输入中使用相同的名称在特定列中插入数据。

通过从SQL请求数据来动态创建表单，这就是每个输入具有相同名称的原因。

这是我的代码：

<?php

if(!empty($_POST)){
    $name = $_POST['name'];
    $description = $_POST['description'];
    $result = $_POST['result'];


    $db = Database::connect();
    $datenow = date("Y-m-d H:i:s");

    $start = $db->prepare("INSERT INTO trainings (user,program,date) values(?, ?, ?)");
    $start->execute(array($userId,$id,$datenow));

    $getid = $db->query("SELECT tid AS trainingid FROM trainings WHERE user = $userId AND tid = LAST_INSERT_ID()");
    $trainingIds = $getid->fetch();
    $trainingLastId = $trainingIds['trainingid'];

    for($i = 0; $i < count($_POST['result']); $i++){

        $textResult = array_merge($name,$result);
        $text = implode($textResult);

        $insert = $db->prepare("UPDATE trainings SET trainings.results = '$text' WHERE tid = $trainingLastId");
        $insert->execute();
    }

    Database::disconnect();
    //header("Location: index.php");
} ?>

形式：

            $db = Database::connect();
        global $userId;

        $exercices = $db->query("SELECT exercices.id, exercices.user, exercices.program, exercices.name, exercices.type, exercices.duration, programs.id AS program FROM exercices LEFT JOIN programs ON exercices.program = programs.id WHERE exercices.program = $id AND exercices.user = '" . $userId . "'");
        $nexercices = $exercices->fetch();
        if ($nexercices['program'] == 0){
            echo "Nothing";
        }
        else {
            $listExercices = $db->query("SELECT exercices.name, exercices.description, exercices.type, exercices.duration FROM exercices WHERE program = $id AND user = '" . $userId . "'");
            $listExercice = $listExercices->fetchAll();
            echo '<form method="post" action="" class="uk-grid-small" uk-grid>';
            foreach($listExercice AS $exercice){
                if($exercice['type'] == 'Repos'){
                    echo '<div class="uk-width-1-2@s">';
                    echo '<input class="uk-input" type="text" name="name[]" value="' . $exercice['name'] . '" readonly>';
                    echo '</div>';
                    echo '<div class="uk-width-1-2@s">';
                    echo '<input class="uk-input" type="text" name="duration[]" value="' . $exercice['duration'] . '" readonly>';
                    echo '</div>';
                }
                else {
                    echo '<div class="uk-width-1-2@s">';
                    echo '<input class="uk-input" type="text" name="name[]" value="' . $exercice['name'] . '" readonly>';
                    echo '<input class="uk-input uk-form-blank" name="description[]" value="' . br2nl($exercice['description']) . '" readonly>';
                    echo '</div>';
                    echo '<div class="uk-width-1-2@s">';
                    echo '<p>Résultat</p>';
                    echo '<input class="uk-input" type="text" name="result[]" value="">';
                    echo '</div>';
                }
            }
            echo '<button type="submit" class="uk-button uk-button-primary">Create</button>';
            echo '</form>';
        }
        Database::disconnect();

由于SQL中有各种数据，它将生成输入“name”和另一个输入“result”。

实际上它工作得很好，但是在我的SQL表中，如果我有两个输入（名称和结果），我会看到插入的数据：namenameresultresult

我想在我的sql表中格式化它：

<p>Name : Result</p>
<p>Name : Result</p>

有谁知道我该怎么办？

谢谢：）

Answer 1

将for循环修改为如下所示：

for($i = 0; $i < count($_POST['result']); $i++){
    $textResult = $name[$i]." : ".$result[$i]; 
    $insert = $db->prepare("UPDATE trainings SET trainings.results = '$textResult' WHERE tid = $trainingLastId");
    $insert->execute(); }

并在<p>标记中回显：

<p><?php echo $yourrecord; ?> </p>

或

$textResult = "<p>".$name[$i]." : ".$result[$i]."</p>";

如果必须添加标记

使用相同名称在SQL中使用多个输入格式化插入的数据

1 个答案: