你能用下面的代码帮助我找出我所遗漏的内容吗?我正在使用Eclipse。
Scanner scanner = new Scanner(System.in);
String input = scanner.nextLine();
{
if (input.equalsIgnoreCase(("front door") || ("front") || ("basement") || ("basement entrance")))
if (input.equalsIgnoreCase(("front door") || ("front"))
System.out.println("Maggie went to the side of the home and open the basement door. As the door opened, she could smell the dust from inside.");
else
if ((input.equalsIgnoreCase("basement") || ("basement entrance")))
System.out.println("Maggie walks up the steps and slowly opens the front door.");
else
System.out.println("That is not a correct answer");
答案 0 :(得分:0)
这不是你使用逻辑或运算符的方式,你必须做类似
的事情if (input.equalsIgnoreCase("front door") || input.equalsIgnoreCase("front") ||
input.equalsIgnoreCase("basement") || input.equalsIgnoreCase("basement entrance")) {
...
}
答案 1 :(得分:0)
我认为有一些错误: 1. If-else逻辑:
a)if(input.equalsIgnoreCase((“front door”)||(“front”)|| (“地下室”)|| (“地下室入口”))) if(input.equalsIgnoreCase((“front door”)||(“front”))
你在这里是什么意思?第二,如果是多余的。 b)
否则
if((input.equalsIgnoreCase(“basement”)||(“basement entrance”)))
此部分无法访问,因为如果覆盖它。
假设它看起来应该是llke
String input = scanner.nextLine();
{
input = input.toLowerCase();
if (input.equals("front door") || input.equals("front"))
System.out.println("Maggie went to the side of the home and open the basement door. As the door opened, she could smell the dust from inside.");
else if (input.equals("basement") || input.equals("basement entrance"))
System.out.println("Maggie walks up the steps and slowly opens the front door.");
else
System.out.println("That is not a correct answer");