Question

web.py＆＃39;你好，世界＆＃39;示例在Ubuntu 14.04上的Apache上出现404错误：＆＃34;在此服务器上找不到请求的URL / api /。＆＃34;

我按照这些说明操作：http://webpy.org/cookbook/mod_wsgi-apache-ubuntu

Apache 000-default.conf：

<VirtualHost *:80>
  ServerAdmin webmaster@localhost
  DocumentRoot /var/www/html

  WSGIScriptAlias /api /var/www/html/webpy-app/code.py
  AddType text/html .py

  ...

  <Directory /var/www/html>
      Options Indexes FollowSymLinks MultiViews
      AllowOverride FileInfo
      Order allow,deny
      allow from all
      AddHandler mod_python .py
      PythonHandler mod_python.publisher
      PythonDebug On
  </Directory>
</VirtualHost>

code.py，它给出了404错误：

import web

 urls = (
     '/.*', 'hello',
     )

 class hello:
     def GET(self):
         return "Hello, world."

 application = web.application(urls, globals()).wsgifunc()

wsgi正在运作，例如如果我将以下内容放入code.py，它可以工作（取自http://modwsgi.readthedocs.io/en/develop/user-guides/checking-your-installation.html#embedded-or-daemon-mode）：

import sys

def application(environ, start_response):
    status = '200 OK'
    output = u'wsgi.multithread = %s' % repr(environ['wsgi.multithread'])

    response_headers = [('Content-type', 'text/plain'),
                        ('Content-Length', str(len(output)))]
    start_response(status, response_headers)

    return [output.encode('UTF-8')]

Answer 1

啊 - 通过添加修复：

<Files code.py>
    SetHandler wsgi-script
    Options ExecCGI FollowSymLinks
</Files>

到Apache 000-default.conf，我在http://webpy.org/install#apache

找到了

找不到Ubuntu Apache wsgi web.py 404

1 个答案: