Question

我理解如何从函数中传递变量，但我一直坚持将多个函数组合在一起？我想将函数中存储的所有double值添加到一个名为＆＃34; totalBillAmount＆＃34;的函数中。（navyCreditBill + wfStudentBill + ....等）。此外，有没有办法结合功能，即使他们都有不同的双重值？（即将所有票据合并成一个名为票据的函数）

//this is my main file
Budget budget;

budget.introText();
double inputNavyCreditCardBill = budget.navyCreditBill();
double inputWellsStudentLoanBill = budget.wfStudentBill();
double inputSprintPhoneBill = budget.sprintBill();
double carBill = budget.carBill();
double capitalOneCreditCard = budget.capitalCredit();
double fedStudentLoan = budget.fedCreditBill();
double navyPersonalLoan = budget.navyPersonalLoan();
double totalMoneyOnHand = budget.totalMoneyOnHand();
double totalBillAmount = 

    double moneyRemaining = totalMoneyOnHand - totalBillAmount;
    std::cout << std::endl << "Money Remaining: $" << moneyRemaining << std::endl;

    double extraMoneyTowardsDebt = moneyRemaining * .7;
    std::cout << std::endl << "Extra Money For Debt: $" << extraMoneyTowardsDebt << std::endl;

    double moneyFromCreditForGirlFriend = moneyRemaining * .3;
    std::cout << "Extra Money From Credit For Girlfriend!: $" << moneyFromCreditForGirlFriend << std::endl;

    double extraMoneyForMe = moneyRemaining * .3;
    std::cout << "MA MONEY BITCH: $" << extraMoneyForMe << std::endl;
return 0;
}

Answer 1

假设您有以下功能：

void func1(int bar1) { ... }
void func2(int bar2) { ... }
void func3(int bar3) { ... }

如果你想将所有这些函数组合在一个新的更大的函数中，你需要做的就是通过大函数的参数列表传递每个小函数所需的参数：

void bigFunc(int bar1, int bar2, int bar3) {
  ...
  func1(bar1);
  func2(bar2);
  func3(bar3);
}

现在，在您的情况下，您还有返回值，这会使事情变得更复杂一些。根据您对这些操作的要求，您可以在big函数中进行计算，然后返回单个结果，或者使用数组，结构或更复杂的容器来存储单独的结果。

因为在你的情况下你只想返回一个结果，这很容易。您可以在下面看到包含大量函数的示例（double sum(double, double, double)，double pow(double, double)和double sub(double, double)）。您应该能够根据您的场景进行调整：

// Use the arguments list of bigFunc to pass down the arguments that each of the smaller function requires
void bigFunc(double arg1, double arg2, double arg3) {

  // Use temporary variables to store the return value of each smaller function
  double s = sum(arg1, arg2, arg3);
  double p = pow(arg1, arg3);
  double sb = sub(arg1, arg2);

  // Do whatever you want we the results and return it
  return s + p - sb;
}

如何将多个功能合并为一个？

1 个答案: