Question

我使用json2csharp生成了类。 var content = response.Content;中有好处我也对主要类进行了反序列化：

var responseData1 = JsonConvert.DeserializeObject<RootObjectChangeLocation>(content);

但是我需要从这个类中检索lat和lng：

public class Location
{
    public double lat { get; set; }
    public double lng { get; set; }
}

我试图让var responseData1 = JsonConvert.DeserializeObject<Location>(content);来检索坐标。但如果直接执行此操作，则lat中的lng和responseData1为空。我怎么能得到它们？这是由json2csharp生成的代码：

 public class AddressComponent
    {
        public string long_name { get; set; }
        public string short_name { get; set; }
        public List<string> types { get; set; }
    }

    public class Northeast
    {
        public double lat { get; set; }
        public double lng { get; set; }
    }

    public class Southwest
    {
        public double lat { get; set; }
        public double lng { get; set; }
    }

    public class Bounds
    {
        public Northeast northeast { get; set; }
        public Southwest southwest { get; set; }
    }

    public class Location
    {
        public double lat { get; set; }
        public double lng { get; set; }
    }

    public class Northeast2
    {
        public double lat { get; set; }
        public double lng { get; set; }
    }

    public class Southwest2
    {
        public double lat { get; set; }
        public double lng { get; set; }
    }

    public class Viewport
    {
        public Northeast2 northeast { get; set; }
        public Southwest2 southwest { get; set; }
    }

    public class Geometry
    {
        public Bounds bounds { get; set; }
        public Location location { get; set; }
        public string location_type { get; set; }
        public Viewport viewport { get; set; }
    }

    public class Result
    {
        public List<AddressComponent> address_components { get; set; }
        public string formatted_address { get; set; }
        public Geometry geometry { get; set; }
        public string place_id { get; set; }
        public List<string> types { get; set; }
    }

    public class RootObjectChangeLocation
    {
        public List<Result> results { get; set; }
        public string status { get; set; }
    }

jsonString是：

{
   "results" : [
      {
         "address_components" : [
            {
               "long_name" : "Vinnytsia",
               "short_name" : "Vinnytsia",
               "types" : [ "locality", "political" ]
            },
            {
               "long_name" : "Vinnyts'ka city council",
               "short_name" : "Vinnyts'ka city council",
               "types" : [ "administrative_area_level_3", "political" ]
            },
            {
               "long_name" : "Vinnyts'ka oblast",
               "short_name" : "Vinnyts'ka oblast",
               "types" : [ "administrative_area_level_1", "political" ]
            },
            {
               "long_name" : "Ukraine",
               "short_name" : "UA",
               "types" : [ "country", "political" ]
            }
         ],
         "formatted_address" : "Vinnytsia, Vinnyts'ka oblast, Ukraine",
         "geometry" : {
            "bounds" : {
               "northeast" : {
                  "lat" : 49.27902,
                  "lng" : 28.5710879
               },
               "southwest" : {
                  "lat" : 49.190448,
                  "lng" : 28.3681799
               }
            },
            "location" : {
               "lat" : 49.233083,
               "lng" : 28.468217
            },
            "location_type" : "APPROXIMATE",
            "viewport" : {
               "northeast" : {
                  "lat" : 49.27902,
                  "lng" : 28.5710879
               },
               "southwest" : {
                  "lat" : 49.1906116,
                  "lng" : 28.3681799
               }
            }
         },
         "place_id" : "ChIJiWRaGWVbLUcR_nTd7lnh1Ms",
         "types" : [ "locality", "political" ]
      }
   ],
   "status" : "OK"
}

Answer 1

@dbc帮我找到了根据这个link

的解决方案

        get_coordinates.Click += delegate
        {
            string city_val = change_location.Text;
            var client = new RestClient("https://maps.googleapis.com/maps/api/geocode/json?address=");
            var request = new RestRequest(city_val, Method.GET);
            IRestResponse response = client.Execute(request);
            var content = response.Content;

            var responseData1 = JsonConvert.DeserializeObject<RootObjectChangeLocation>(content);

            if (content == null||content=="")
            {
                Toast.MakeText(this, "City is empty or incorrect", ToastLength.Short).Show();
            }
            else
            {
                foreach(var data in responseData1.results)
                {
                    var lat = data.geometry.location.lat;
                }
            }
            // Toast.MakeText(this, content, ToastLength.Long).Show();
            Console.WriteLine(content.ToString());
        };

带有嵌套类c＃的复杂反序列化json

1 个答案: