我有以下问题:
SELECT BusID, count(BusID) as 'NoofConnections'
FROM mytable
Group By BusID
Order by BusID
我得到了下表:
BusID NoofConnections
=========================
1 6
2 6
4 3
5 2
3 1
我将从NoofConnections中选择最大值,因此在这种情况下,LIMIT 1不起作用,因此我们有两个相等的值。像这样:
BusID NoofConnections
=========================
1 6
2 6
任何想法?
答案 0 :(得分:2)
您可以使用子查询:
SELECT BusID, COUNT(*) as NoofConnections
FROM mytable
GROUP BY BusID
HAVING COUNT(*) = (SELECT COUNT(*)
FROM mytable
GROUP BY BusID
ORDER BY COUNT(*) DESC
LIMIT 1
)
ORDER BY BusID;
答案 1 :(得分:0)
您可以使用子选择
select * from (
SELECT BusID, count(BusID) as NoofConnections
FROM mytable
Group By BusID
) t1
where t1.NoofConnections = ( select max(NoofConnections)
from (
SELECT BusID, count(BusID) as NoofConnections
FROM mytable
Group By BusID
)