我正在编辑表单并在带有电影标题的下拉框中。 其中一个应该被选中,所以说DVD_id:100。 如何在下面的代码中完成这项工作?
<div class="form-group">
<label for="Site name" class="col-md-4 control-label">DVD Title</label>
<?php
$query = "Select DISTINCT dvd.dvdname, dvd.dvd_id, FROM DVD where ORDER BY dvd.dvdname";
$result = mysql_query($query) or die ("Couldn�t execute query.");?>
<div class="col-md-8">
<select id="box" name="dvdtitlefield" class="selectpicker form-control" multiple title="Choose one of the following..." >
<?php
while ($row = mysql_fetch_assoc($result))
{
extract($row);
echo '<option value="'. $dvd_id .'">'. $dvdname .'</option>';
}?>
</select>
</div>
</div>
答案 0 :(得分:0)
使用option标签的selected属性默认选择
<select>
<option value="tiger">tiger</option>
<option value="lion">lion</option>
<option value="zebra">zebra</option>
<option value="cat" selected>cat</option>
</select>
在您的代码中,您可以检查默认情况下要选择的选项并为其应用if条件
例如
<div class="form-group">
<label for="Site name" class="col-md-4 control-label">DVD Title</label>
<?php
$query = "Select DISTINCT dvd.dvdname, dvd.dvd_id, FROM DVD where ORDER BY dvd.dvdname";
$result = mysql_query($query) or die ("Couldn�t execute query.");?>
<div class="col-md-8">
<select id="box" name="dvdtitlefield" class="selectpicker form-control" multiple title="Choose one of the following..." >
<?php
while ($row = mysql_fetch_assoc($result))
{
extract($row);
if($dvd_id==100)
{
echo '<option value="'. $dvd_id .'" selected>'. $dvdname .'</option>';
}
else
{
echo '<option value="'. $dvd_id .'">'. $dvdname .'</option>';
}
}?>
</select>
</div>
</div>