我尝试从LEGACY数据库模式中创建一个jpa模型。
我在mysql中创建了一个简单的数据库,我在eclipse(Reverse)中使用jpa工具生成了模型。
jpa工具生成的代码在我的springboot项目中出错:
org.springframework.beans.factory.BeanCreationException:创建名为'entityManagerFactory'的bean时出错 在类路径资源中定义[org / springframework / boot / autoconfigure / orm / jpa / HibernateJpaAutoConfiguration.class]:
调用init方法失败;嵌套异常是org.hibernate.AnnotationException:stackoverflow.entity.SecondTable.mainTable的referencedColumnNames(id) 引用stackoverflow.entity.MainTable未映射到单个属性
我认为这是有道理的,因为在SecondTable中我的PK是(id,day),而在MainTable中是(id,year,month,code)。 现在的想法是让id与之相关。
几个链接: https://gigsterous.github.io/engineering/2016/09/25/spring-boot-2.html
对于属性覆盖(可能指定哪个列不相关) http://techqa.info/programming/question/33620473/hibernate-bidirectional-one-to-many-with-composite-key
JPA: Entity mapping with composite primary key and single key
这些是由jpa工具创建的4个实体:
@Entity
@Table(name="main_table")
public class MainTable implements Serializable {
private static final long serialVersionUID = 1L;
@EmbeddedId
private MainTablePK id;
private String comment;
//bi-directional many-to-one association to SecondTable
@OneToMany(mappedBy="mainTable")
private List<SecondTable> secondTables;
public MainTable() {
}
}
@Embeddable
public class MainTablePK implements Serializable {
//default serial version id, required for serializable classes.
private static final long serialVersionUID = 1L;
private int id;
private String year;
private String month;
private String code;
public MainTablePK() {
}
}
@Entity
@Table(name="second_table")
public class SecondTable implements Serializable {
private static final long serialVersionUID = 1L;
@EmbeddedId
private SecondTablePK id;
//bi-directional many-to-one association to MainTable
//I think I don’t need a bi-directional relationship, just from MainTable to SecondTable
//ERROR: NOT MAPPED TO A SINGLE PROPERTY
//I understand id in MainTable is a composite Key
@ManyToOne
@JoinColumn(name="id", referencedColumnName="id")
private MainTable mainTable;
public SecondTable() {
}
}
@Embeddable
public class SecondTablePK implements Serializable {
//default serial version id, required for serializable classes.
private static final long serialVersionUID = 1L;
private int id;
private int day;
private int value1;
private int value2;
private int value3;
public SecondTablePK() {
}
}
SCRIPT SQL和数据示例
DROP TABLE IF EXISTS `main_table`;
CREATE TABLE `main_table` (
`id` int(11) NOT NULL AUTO_INCREMENT,
`year` char(4) NOT NULL,
`month` char(2) NOT NULL,
`code` char(6) NOT NULL,
`comment` varchar(45) DEFAULT NULL,
PRIMARY KEY (`id`,`year`,`month`,`code`)
) ENGINE=InnoDB AUTO_INCREMENT=2 DEFAULT CHARSET=latin1;
INSERT INTO `main_table` VALUES (1,'2017','01','333090','coment one');
This has a composite key
DROP TABLE IF EXISTS `second_table`;
CREATE TABLE `second_table` (
`id` int(11) NOT NULL,
`day` int(11) NOT NULL,
`value1` int(11) DEFAULT NULL,
`value2` int(11) DEFAULT NULL,
`value3` int(11) DEFAULT NULL,
PRIMARY KEY (`id`,`day`)
) ENGINE=InnoDB DEFAULT CHARSET=latin1;
INSERT INTO `second_table` VALUES (1,0,1,NULL,NULL),(1,1,2,NULL,NULL),(1,2,NULL,NULL,NULL),(1,3,NULL,NULL,NULL),(1,4,NULL,NULL,NULL),(1,32,NULL,NULL,NULL);
可以使用JPA实现吗? 有什么建议吗?
由于
更新
删除了非PK字段value1,value2和value3,这是一个错字。
遵循JPA 2.1规范,第2.4.3节,示例2,第34,35页与我的非常相似。
所以申请:
@MapsId("empPK")
@JoinColumns({
@JoinColumn(name="FK1", referencedColumnName="firstName"),
@JoinColumn(name="FK2", referencedColumnName="lastName") })
我们有:
@ManyToOne
@MapsId("id") // maps the 'id' attribute of the embedded ID
@JoinColumn(name="id", referencedColumnName="id")
private MainTable mainTable;
不再进行任何更改。
我收到下一个错误: org.springframework.beans.factory.BeanCreationException:在类路径资源[org / springframework / boot / autoconfigure / orm / jpa / HibernateJpaAutoConfiguration.class]中定义名称为'entityManagerFactory'的bean创建错误:init方法的调用失败;嵌套异常是org.hibernate.AnnotationException:无法在@MapsId映射中找到列引用:代码
如果我删除代码,同样的错误,但月,如果我删除月份,则与年相同的错误。
由于
答案 0 :(得分:0)
首先,您的SecondTablePK
似乎不正确,因为它包含非PK字段value1
,value2
和value3
。它应该看起来像这样:
@Embeddable
public class SecondTablePK implements Serializable {
//default serial version id, required for serializable classes.
private static final long serialVersionUID = 1L;
private int id;
private int day;
public SecondTablePK() {
}
}
关于共享id
:通常,从属实体将引用父实体的整个主键,但您可以像这样映射关系:
@Entity
@Table(name="second_table")
public class SecondTable implements Serializable {
private static final long serialVersionUID = 1L;
@EmbeddedId
private SecondTablePK id;
private int value1;
private int value2;
private int value3;
@ManyToOne
@MapsId("id") // maps the 'id' attribute of the embedded ID
@JoinColumn(name="id", referencedColumnName="id")
private MainTable mainTable;
public SecondTable() {
}
}
这就像“派生身份”,在JPA 2.1规范第2.4.1节中讨论过。