Question

我需要你的帮助，因为我希望尽可能少地优化这些查询...

我想获得以下警报的计数：
companies -> sites -> interventions -> purchases -> alerts

我想得到以下行动的计数：
contractors -> actions
companies -> actions

我执行以下操作，但每页上的7个请求并不是很好：/

$companies = Company::where('id', '=', Auth::user()->userable_id)->orWhere('company_id', '=', Auth::user()->userable_id)->pluck('id')->toArray();
$contractors = Contractor::where('id', '=', Auth::user()->userable_id)->orWhere('company_id', '=', Auth::user()->userable_id)->pluck('id')->toArray();

$cp = array_merge($companies, $contractors);

$sites = Site::whereIn('company_id', $companies)->pluck('id')->toArray();
$interventions = Intervention::whereIn('site_id', $sites)->pluck('id')->toArray();
$purchases = Purchase::whereIn('intervention_id', $interventions)->pluck('id')->toArray();
$bubblecounts['alerts'] = Alerts::whereIn('purchase_id', $purchases)->where('status', 0)->whereDate('alert_date', '!=', '0000-00-00 00:00:00')->count();
$bubblecounts['actions'] = Action::whereIn('actionable_id', $cp)->where([['status', 0], ['alert_date', '!=', null]])->count();

你能帮帮我吗？谢谢！

Answer 1

我能想到的一个优化是：

$alerts = Alerts::whereIn('purchase_id', $purchases)->where('status', 0)->whereDate('alert_date', '!=', '0000-00-00 00:00:00')->count();
$actions = Action::whereIn('actionable_id', $cp)->where([['status', 0], ['alert_date', '!=', null]])->count();

$bubblecounts['alerts'] = $alerts;
$bubblecounts['actions'] = $actions;

而不是获取整行，它只获得计数。如果没有大量的警报和操作，您将获得良好的性能提升。

Laravel Eloquent指望whereIn（）5关系深

1 个答案: