Question

我在使用自动生成的别名调用子类属性时遇到问题。

这是我使用getSQL（）函数打印的查询部分。我可以看到在查询中已经生成了别名。

SELECT r0_.id AS id0, r0_.title AS title1, r0_.created_at AS created_at5, r0_.updated_at AS updated_at6, r1_.date AS date7, r1_.job AS job8, r2_.date AS date13, r2_.time AS time14, r2_.job AS job15
FROM reports r0_ 
LEFT JOIN reports_small_works r1_ ON r0_.id = r1_.id 
LEFT JOIN reports_call_out r2_ ON r0_.id = r2_.id 
WHERE r0_.division_id = 1
ORDER BY r0_.id 
DESC

如何使用reports_call_out别名？报告是父类和Reports_Call_out＆amp; Reports_small_works都是子类，并在Query中附加为LeftJoin默认值。

Answer 1

我的猜测是，reports_call_out没有＆＃34; job＆＃34;列，您正在尝试选择它。你可以使用getDQL（）函数发布你的DQL吗？要使用连接表别名，请在连接后传递它，如下所示：

SELECT ...
FROM reports r //r is alias for reports here
LEFT JOIN r.reports_call_out rco ...//rco is alias for reports_call_out here

或者，如果您使用QueryBuilder，请将其传递出去：

/* ReportsRepository.php */
$this->createQueryBuilder('r')//r is alias for reports here
->select('...')
->leftJoin('r.reports_call_out', 'rco')//rco is alias for reports_call_out here

Symfony 2：[语义错误]第0行，col 489附近＆＃39; r2_.job LIKE＆＃39;：错误：＆＃39; r2 _＆＃39;没有定义

1 个答案: