Question

我的搜索查询出现问题，在多次搜索网站后，网站崩溃，我不确定是否是由于我在GoDaddy支付的内存不足或者我的搜索查询是抛出错误或要求太多资源。

请问您可以在此处测试搜索：http://cameras.specced.co.uk

请输入几种不同的相机型号并多次执行此操作，搜索查询将停止工作，网站将不再有效。

以下是搜索查询：

$model_search_query = $cameras_pdo->prepare("SELECT * FROM models WHERE concat_ws(' ',brand_name,model) LIKE :search LIMIT 5");
$model_search_query->execute(array(':search' => "%" . $_POST['search'] . "%"));

while ($model_search = $model_search_query->fetch(PDO::FETCH_ASSOC)) {
    $brand_search_query = "SELECT brand FROM brands WHERE id =" . $model_search['brand']; 
    $brand_search = mysqli_fetch_assoc(mysqli_query($cameras, $brand_search_query)); ?>

        <a href="compare.php?compare_1=<?php echo $model_search['id'];?>">



        <div class="search_result">
            <div class="search_result_image">
                <!--  IMAGE REMOVED TO TEST IF THIS WAS CAUSING THE ISSUE -->
            </div>

            <div class="search_result_text">
                <?php echo $brand_search['brand'] . " " . $model_search['model']; ?>
            </div>
        </div>
    </a>
 <?php } ?>

我已经从搜索结果中删除了图片，只是因为它太大而且在下拉搜索中同时加载了太多导致问题，但是网站在搜索了几次后仍然崩溃。

这是我在Safari中收到的错误，

Safari无法打开....因为服务器意外断开连接...

感谢您的任何帮助

编辑：

以下是我的fetch.php的全部内容，当用户搜索http://cameras.specced.co.uk标题中右上角的搜索栏时，AJAX会包含该内容。

<?php ini_set('display_errors', 'On'); ?>

<!-- REQUIRE DB -->
<?php 
    $servername = "xxx";
    $username = "xxx";
    $password = "xxx";
    $dbname = "xxx";
?>
<?php
    $cameras = mysqli_connect($servername, $username, $password, $dbname);

    $cameras_pdo = new PDO('mysql:host=xxx;dbname=xxx', 'xxx', 'xxx'); 
?>


<?php 


    $model_search_query = $cameras_pdo->prepare("SELECT * FROM models WHERE concat_ws(' ',brand_name,model) LIKE :search LIMIT 5");
    $model_search_query->execute(array(':search' => "%" . $_POST['search'] . "%"));

    while ($model_search = $model_search_query->fetch(PDO::FETCH_ASSOC)) {
        $brand_search_query = "SELECT brand FROM brands WHERE id =" . $model_search['brand']; 
        $brand_search = mysqli_fetch_assoc(mysqli_query($cameras, $brand_search_query));
p?1=' . $_POST['current'] . "&2=" . $model_search['id'] . '">'; 

            echo '<a href="compare.php?compare_1=' . $model_search['id'] . '">'. 

            '<div class="search_result">' .
                '<div class="search_result_image">' .
                    '<img src="http://www.specced.co.uk/images/cameras/[' . $model_search['id'] . ']_front.png">' .
                '</div>' .

                '<div class="search_result_text">' .
                    $brand_search['brand'] . " " . $model_search['model'] . 
                '</div>' .
            '</div>' .
        '</a>';
    }

?>

Answer 1

当网站停止响应时，如果您在浏览器“网络”面板中检查开发者控制台并检查来自fetch.php的响应，您将看到最后一个HTTP 200响应仅包含以下内容：

<!-- REQUIRE DB -->

后续请求为空白。因此，我猜测PHP在尝试建立数据库连接时会死掉。检查您的error_log并在此处发布您的错误作为评论！完成后关闭数据库连接吗？

MYSQLI搜索查询崩溃了GoDaddy Site服务器

1 个答案: