Question

我有一张桌子，想要使用where执行以下操作。我想选择NUM_ORDERS = 1 CHANNEL_ID in (1,2,3,4)所有行以及NUM_ORDERS > 1和CHANNEL_ID in (1,2,3)所有行。我如何结合这两个条件？

感谢您的帮助。

Answer 1

以下SQL查询应该这样做。请注意，由于运算符优先级，我在where子句中使用的括号不是必需的。

 SELECT *
    FROM [put_your_table_here]
    WHERE (NUM_ORDERS = 1 AND CHANNEL_ID IN (1,2,3,4)) OR (NUM_ORDERS > 1 AND CHANNEL_ID IN (1,2,3))

Answer 2

您可以使用UNION，它结合了查询＃1和查询＃2的结果。

select * from [table] where NUM_ORDERS = 1 AND CHANNEL_ID in (1,2,3,4) 
UNION
select * from [table] where NUM_ORDERS > 1 AND CHANNEL_ID in (1,2,3);

默认情况下，UNION运算符仅选择不同的值。要允许重复值，请使用UNION ALL：

select * from [table] where NUM_ORDERS = 1 AND CHANNEL_ID in (1,2,3,4) 
UNION ALL
select * from [table] where NUM_ORDERS > 1 AND CHANNEL_ID in (1,2,3);

另一个更好的解决方案是使用像这样的OR子句;

SELECT * from [table] where (NUM_ORDERS = 1 AND CHANNEL_ID in (1,2,3,4)) or (NUM_ORDERS > 1 and CHANNEL_ID in (1,2,3));

Answer 3

您有几个选择：

使用OR：

SELECT...
WHERE (NUM_ORDERS = 1 AND CHANNEL_ID in (1,2,3,4))
OR
(NUM_ORDERS > 1 and CHANNEL_ID in (1,2,3))

或者，将两者联合起来：

SELECT...
WHERE NUM_ORDERS = 1 AND CHANNEL_ID in (1,2,3,4)
UNION
SELECT...
WHERE NUM_ORDERS > 1 and CHANNEL_ID in (1,2,3)

Answer 4

这将是这样的：

SELECT * 
FROM tableName
WHERE (NUM_ORDERS = 1 AND CHANNEL_ID IN (1,2,3,4))
OR (NUM_ORDERS > 1 AND CHANNEL_ID IN (1,2,3))

哪里有不同的条件

4 个答案: