如何在c#中使用RestSharp POST方法发送json数据

时间:2017-06-16 06:18:15

标签: c# angular restsharp

我将使用RestSharp测试REST API,并且需要post方法来发布数据并基于回调给出状态(错误,无效,成功),即发出INVALID,即“对象引用未设置为对象的实例”{{ 3}}

这是我的TestMethod

     [TestMethod()]
            public void AddNewBFormat()
            {
            Random r = new Random((int)DateTime.Now.Ticks);
            var x = r.Next(100000, 999999);
            string s = x.ToString("000000");

            string UniqueFileName = "S" + s + DateTime.Now.ToString("yyyyMMdd") + ".xlsx";
            request.Resource = "api/BFormat/AddNewBFormat";
            request.Method = Method.POST;
            var body= "{'UploadFileVM':{'BordereauxId':null,'BFormatId':null,'FileName':'"+UniqueFileName+ "','Filesize':0,'Path':'C:\\Applications\\new\\\\TempUploadedFiles','size':0,'ActiveSheetIndex':0,'HeaderIndex':0,'MultiHeaders':null,'SheetNames':null,'IsPasswordProtected':false},'BFormat':{'UniqueFileName':'"+ UniqueFileName+"'}}";
            request.RequestFormat = DataFormat.Json;
            request.AddHeader("Content-type", "application/json");
            request.AddParameter("Application/Json", body, ParameterType.RequestBody);
            var queryResult = client.Execute<ResponseData<Guid>> (request).Data;
            try
            {
                Assert.IsTrue(queryResult.ReturnData != null);

            }
            catch (Exception ex)
            {
                Assert.Fail(ex.Message);
            }
            }

我已尝试过request.addJsonBody,但我想知道使用POST方法发送json数据的相同结果

1 个答案:

答案 0 :(得分:0)

在您的web api中,您需要处理绑定的json数据。 WebApi通常会自行完成。 而且你也不必用&#34; application / json&#34;添加标题或任何参数。 如果您只需使用AddJsonBody(object obj)方法,RestSharp将自动设置标题。

或者另一种方法是:

    Random r = new Random((int)DateTime.Now.Ticks);
    var x = r.Next(100000, 999999);
    string s = x.ToString("000000");
    string UniqueFileName = "S" + s + DateTime.Now.ToString("yyyyMMdd") + ".xlsx";
    request.Resource = "api/BFormat/AddNewBFormat";
    request.Method = Method.POST;
    request.RequestFormat = DataFormat.Json;
    var body = new
    {
        UploadFileVM = new
        {
            BordereauxId = "",
            BFormatId = "",
            FileName = UniqueFileName,
            Filesize = 0,
            Path = @"c:\sdakdldas\"
        }
    };
    request.AddBody(body); //enter code herE
    var queryResult = client.Execute<ResponseData<Guid>>(request).Data;
    try
    {
        Assert.IsTrue(queryResult.ReturnData != null);

    }
    catch (Exception ex)
    {
        Assert.Fail(ex.Message);
    }

不要自己序列化数据。 RestSharp将负责序列化。