我有一个tableView和tableViewCell。我创建了MenuController来进行setTableView编辑。但似乎失败了。但我使用导航按钮添加“testFunc”动作。它可以改变mutiselected编辑。我怎么想念它呢?我已经添加了tableView的子视图。我还遵循UITableViewDataSource,UITableViewDelegate。
protocol DelegateA {
func testFunc()
}
class ViewController: UIViewController,DelegateA {
lazy var tableView:UITableView = { ()->UITableView in
let ui:UITableView = UITableView()
ui.delegate = self
ui.dataSource = self
ui.separatorStyle = .none
ui.backgroundColor = defaultBackgroundColor
return ui
}()
override func viewDidLoad() {
super.viewDidLoad()
self.tableView.allowsMultipleSelectionDuringEditing = true
}
func testFunc() {
print("123") //it print "123" successful
//not working
if(self.tableView.isEditing == false) {
self.tableView.setEditing(true, animated:true)
}
else {
self.tableView.setEditing(false, animated:true)
}
}
}
这是自定义tableViewCell的标签
class UITalkContent:UILabel {
var delegate:DelegateA?
override init(frame: CGRect) {
super.init(frame:frame)
translatesAutoresizingMaskIntoConstraints = false
numberOfLines = 0
isUserInteractionEnabled = true
addGestureRecognizer(UILongPressGestureRecognizer(target: self, action: #selector(gestureLongPress)))
}
required init?(coder aDecoder: NSCoder) {
fatalError("init(coder:) has not been implemented")
}
override func drawText(in rect: CGRect) {
let insets: UIEdgeInsets = UIEdgeInsets(top: defaultContentPadding, left: defaultPadding, bottom: defaultContentPadding, right: defaultPadding)
super.drawText(in: UIEdgeInsetsInsetRect(rect, insets))
}
func gestureLongPress(sender:UILongPressGestureRecognizer) {
if (sender.state == .ended) {
return
}
becomeFirstResponder()
let menu = UIMenuController.shared
menu.menuItems = [
UIMenuItem(title: localString(string: "FORWARD"), action: #selector(forward)),
]
menu.setTargetRect(bounds, in: self)
menu.setMenuVisible(true, animated: true)
}
func forward(menu :UIMenuController ) {
print("321") //print "321" successfully
self.delegate = ViewController()
self.delegate?.testFunc()
}
override var canBecomeFirstResponder: Bool{
return true
}
override func canPerformAction(_ action: Selector, withSender sender: Any?) -> Bool {
if (action == #selector(UIResponderStandardEditActions.copy(_:)) || action == #selector(forward)) {
return true
}
return false
}
override func copy(_ sender: Any?) {
UIPasteboard.general.string = text
}
}
2017.06.16更新
class ContentTableViewCell: UITableViewCell {
var labelContent:UILabel = { ()->UILabel in
let ui:UILabel = UITalkContent()
ui.textColor = UIColor(red:0.20, green:0.20, blue:0.20, alpha:1.00)
ui.backgroundColor = UIColor.white
ui.font = defaultTextFont
ui.numberOfLines = 0
ui.lineBreakMode = NSLineBreakMode.byCharWrapping
ui.layer.cornerRadius = defaultButtonRadius
ui.layer.masksToBounds = true
ui.isHidden = false
return ui
}()
override init(style: UITableViewCellStyle, reuseIdentifier: String?) {
super.init(style: style, reuseIdentifier: reuseIdentifier)
loadContent()
}
required init?(coder aDecoder: NSCoder) {
super.init(coder: aDecoder)
}
override func layoutSubviews() {
super.layoutSubviews()
loadVFL()
}
func loadContent() {
contentView.addSubview(labelContent)
}
func loadVFL() {
labelContent.frame = CGRect(x: 0, y: 0, width: contentWidth, height: CGFloat.greatestFiniteMagnitude)
labelContent.sizeToFit()
}
}
答案 0 :(得分:0)
你想知道的事实上是不清楚和模糊的。但我可以在这里看到 您正在以错误的方式protocol-delegation
。要使此过程正确,请按照以下步骤操作:
在您的发件人类中创建一个协议,您希望从中传递任何邮件(在您的情况下:UITalkContent
)
protocol MyProtocol {
func testFunc()
}
class UITalkContent: UILabel {...}
在您的发件人类中添加delegate
var :
class UITalkContent: UILabel {
var delegate: MyProtocol?
...
...
}
使用此delegate
var 调用您在协议中指定的方法。这必须在您的发件人类中以及准备好发送任何邮件时完成。在你的情况下,它是func forward(menu:)
class UITalkContent: UILabel {
...
...
func forward(menu :UIMenuController ) {
...
...
delegate.testFunc()
}
...
...
}
在接收课程中采用协议(在您的情况下:ViewController
)
class ViewController: UIViewController, MyProtocol {
...
...
}
在接收类中实现协议的方法。通知发生时,程序控制将在此处传输。
class ViewController: UIViewController, MyProtocol {
...
...
func testFunc() {
// do what you want to do when program control reaches here
}
...
...
}
现在您必须将接收类设置为该发件人类的delegate
。为此,您必须将self
(接收类)分配给sender类的实例。 (但我没有看到您UILabel
)的任何实例
class ViewController: UIViewController, MyProtocol {
...
...
`instance of UILabel` = self
...
...
}