Question

我需要将数据发送到Zapier webhook，因此，他们更喜欢使用简单的查询字符串。

如何使用PHP循环通过以下JSON响应将其重新组合为单个对象？我需要将它作为一个简单的查询字符串发送到我的Zapier webhook。

具体来说，我真的想在Zapier标签输入字段中使用“标签”和“技术”数据，这意味着我必须将它们作为单独的选项发送，否则所有“标签”和“技术”数据都会被发送作为单个标记，而不是单个标记，就像您希望它们出现一样。

正如您将在下面看到的，某些值具有数组，而其他值具有键/值对。

   {
  "company": {
    "name": "Example Co",
    "legalName": "Example Co LLC",
    "domain": "example.com",
    "domainAliases": [
      "example01.com",
      "example02.com",
      "example03.com"
    ],
    "category": {
      "sector": "Financials",
      "industryGroup": "Diversified Financial Services",
      "industry": "Diversified Financial Services",
      "subIndustry": "Financial Services",
    },
    "tags": [
      "Marketplace",
      "B2C",
      "Financial Services"
    ],
    "foundedYear": null,        
    "tech": [
      "google_analytics",
      "hotjar",
      "outlook",          
    ]
  }
}

我希望它看起来如下（注意在适用的地方附加_0x号码。

{
    "company_name": "Example Co",
    "company_legalName": "Example Co LLC",
    "company_domain": "example.com",
    "company_domainAliases_01": "example01.com",
    "company_domainAliases_02": "example02.com",
    "company_domainAliases_03": "example03.com",
    "category_sector": "Financials",
    "category_industryGroup": "Diversified Financial Services",
    "category_industry": "Diversified Financial Services",
    "category_subIndustry": "Financial Services",
    "category_sicCode": null,
    "category_naicsCode": null,
    "tags": "Marketplace",
    "tags": "B2C",
    "tags": "Financial Services",
    "foundedYear": null,
    "tech_01": "google_analytics",
    "tech_02": "hotjar",
    "tech_03": "outlook",   
}

Answer 1

此代码适用于您的方案。但是如果你需要一个泛型函数，它适用于多个嵌套数组，我们需要编写一个递归函数。

<?php
$json_contents = file_get_contents('test.json'); //Placed your json in test.json 

$output = array();
$json_array = json_decode($json_contents, true); //Convert json to php array 

foreach ($json_array as $element){  
    foreach ($element as $attribute => $value){ //parse through each attribute 
      if(is_array($value)){   //if value is an array, parse through it and update output array accordingly
          foreach ($value as $a => $v) {
            $output[$attribute.'_'.$a] = $v;
          }
      }
      else{      //if value is not an array, get those elements as they are into $output 
          $output[$attribute] = $value;
      }
  }
}
print_r($output);  //You can convert $output into json using json_encode($output);
print_r($json_array);

test.json：

{
  "company": {
    "name": "Example Co",
    "legalName": "Example Co LLC",
    "domain": "example.com",
    "domainAliases": [
      "example01.com",
      "example02.com",
      "example03.com"
    ],
    "category": {
      "sector": "Financials",
      "industryGroup": "Diversified Financial Services",
      "industry": "Diversified Financial Services",
      "subIndustry": "Financial Services"
    },
    "tags": [
      "Marketplace",
      "B2C",
      "Financial Services"
    ],
    "foundedYear": null,
    "tech": [
      "google_analytics",
      "hotjar",
      "outlook"
    ]
  }
}

输出：

Array
(
    [name] => Example Co
    [legalName] => Example Co LLC
    [domain] => example.com
    [domainAliases_0] => example01.com
    [domainAliases_1] => example02.com
    [domainAliases_2] => example03.com
    [category_sector] => Financials
    [category_industryGroup] => Diversified Financial Services
    [category_industry] => Diversified Financial Services
    [category_subIndustry] => Financial Services
    [tags_0] => Marketplace
    [tags_1] => B2C
    [tags_2] => Financial Services
    [foundedYear] => 
    [tech_0] => google_analytics
    [tech_1] => hotjar
    [tech_2] => outlook
)

PHP循环嵌套JSON响应并重新组合为Webhook的简单查询字符串

1 个答案: