Question

我想知道Hive是否可以选择从字符串中获取元素数量，例如david.Udert。我试过这个split(type,'\\.')[2][3]
这split(type,'\\.')[2:3]而且它不起作用，有没有选择做这样的事情来把两个单词放在一起？

Answer 1

数组索引以0

开头

with t as (select 'Now.I.heard.you.know.that.secret.chord' as mycol)

select  split(t.mycol,'\\.')    as arr
   ,split(t.mycol,'\\.')[0] as arr_1st_element
   ,split(t.mycol,'\\.')[1] as arr_2nd_element
   ,split(t.mycol,'\\.')[2] as arr_3nd_element

from    t
;

+----------------------------------------------------------+-----------------+-----------------+-----------------+
|                           arr                            | arr_1st_element | arr_2nd_element | arr_3nd_element |
+----------------------------------------------------------+-----------------+-----------------+-----------------+
| ["Now","I","heard","you","know","that","secret","chord"] | Now             | I               | heard           |
+----------------------------------------------------------+-----------------+-----------------+-----------------+

至少目前不支持数组切片。如果要切片，请在拆分

之前进行切片

with t as (select 'Now.I.heard.you.know.that.secret.chord' as mycol)

select  split(substring_index(substring_index(t.mycol,'.',7),'.',-3),'\\.')     as slice_option_1
   ,split(regexp_extract(t.mycol,'(.*?\\.){4}((\\.?[^.]*){0,3})',2),'\\.')  as slice_option_2

from    t
;

+--------------------------+--------------------------+
|      slice_option_1      |      slice_option_2      |
+--------------------------+--------------------------+
| ["know","that","secret"] | ["know","that","secret"] |
+--------------------------+--------------------------+

Hive split函数获取元素数

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