Question

我有一个发送email和message字段的简单联系表单。我使用的是Mailgun。

我可以从控制台完美地发送电子邮件，但是当我尝试从UI中的表单发送时，我收到以下错误：

protocol String.Chars not implemented for %Iotc.Contact.Email{__meta__: 
#Ecto.Schema.Metadata<:loaded, "contact_emails">, email: 
"cooper.sf@gmail.com", id: 25, inserted_at: ~N[2017-06-15 10:34:26.229957], 
message: "I'd like a cake please.", updated_at: ~N[2017-06-15 10:34:26.229977]}

email_controller.ex

  def create(conn, %{"email" => email_params,
                   "email" => %{"email" => email,
                   "message" => message}}) do

    changeset = Contact.Email.changeset(%Iotc.Contact.Email{}, email_params)
    case Contact.create_email(email_params) do
      {:ok, email} ->
        Iotc.Mailer.send_email(email, message) #<this is the issue.
        conn
        |> put_flash(:info, "Email sent")
        |> redirect(to: email_path(conn, :index))
      {:error, changeset} ->
        conn
        |> put_flash(:error, "Something went wrong")
        |> render("index.html", changeset: changeset)
    end

我尝试过改变

Iotc.Mailer.send_email(email, message)

到

Iotc.Mailer.send_email(email_params)

但我接着

key :to not found in: %{"email" => "cooper.sf@gmail.com", "message" => "I'd like a cake please.", "name" => "Simon"}

Answer 1

模式{:ok, email}使用email结构隐藏外部%Iotc.Contact.Email{}字符串值，而send_email期望第一个参数只是电子邮件地址字符串值。您可以通过email.email：

获取地址值

case Contact.create_email(email_params) do
  {:ok, email} ->
    Iotc.Mailer.send_email(email.email, message)
    ...
  ...
end

或者您可以更改模式以忽略返回的结构，因为您还没有使用它：

case Contact.create_email(email_params) do
  {:ok, _} ->
    Iotc.Mailer.send_email(email, message)
    ...
  ...
end

从表单发送电子邮件 - 协议String.Chars未实现

1 个答案: