Question

I'm surprised why the following code would compile:

#include <stdio.h>

int main(){
    printf("%lu",sizeof(int(123)));
    return 0;
}

the output is 4, what is the meaning of (123) here?

And I found this line of code can compile with g++, but not gcc, what is the reason?

Answer 1

This is C++, the int(123) is a function-style cast to int. It's of course pointless, since 123 is an int-typed literal anyway.

Function-style casts are not part of C, which is why it won't build with a C compiler.

To answer more of the question, what happens is that the operator sizeof is compile-time evaluated to the size (in chars) of its argument. The argument is of type int, so you output the size of int on your platform which is 4.

You could also have used just a plain sizeof 123, which would build in C, or sizeof (int) to be explicit about the type instead of deriving it from a value. Note that the parentheses are part of the argument (the type name is written as a C-style cast), sizeof is not a function.

Answer 2

The sizeof is a keyword, but it is a compile-time operator that determines the size, in bytes, of a variable or data type.

The sizeof operator can be used to get the size of classes, structures, unions and any other user defined data type.

The syntax of using sizeof is as follows:

sizeof (data type) Where data type is the desired data type including classes, structures, unions and any other user defined data type.

Try the following example to understand all the sizeof operator available in C++. Copy and paste following C++ program in test.cpp file and compile and run this program.

#include <iostream>
using namespace std;

int main() {
   cout << "Size of char : " << sizeof(char) << endl;
   cout << "Size of int : " << sizeof(int) << endl;
   cout << "Size of short int : " << sizeof(short int) << endl;
   cout << "Size of long int : " << sizeof(long int) << endl;
   cout << "Size of float : " << sizeof(float) << endl;
   cout << "Size of double : " << sizeof(double) << endl;
   cout << "Size of wchar_t : " << sizeof(wchar_t) << endl;
   return 0;
}

When the above code is compiled and executed, it produces the following result, which can vary from machine to machine:

Size of char : 1
Size of int : 4
Size of short int : 2
Size of long int : 4
Size of float : 4
Size of double : 8
Size of wchar_t : 4

Answer 3

int(123) is an expression with using explicit type conversion.

From the C++ Standard (5.2.3 Explicit type conversion (functional notation))

1 A simple-type-specifier (7.1.6.2) or typename-specifier (14.6) followed by a parenthesized expression-list constructs a value of the specified type given the expression list. If the expression list is a single expression, the type conversion expression is equivalent (in definedness, and if defined in meaning) to the corresponding cast expression (5.4)...

As for the sizeof operator then (C++ STandard, 5.3.3 Sizeof)

1 The sizeof operator yields the number of bytes in the object representation of its operand. The operand is either an expression, which is an unevaluated operand (Clause 5), or a parenthesized type-id...

Thus in this expression

sizeof(int(123))

there is used explicit conversion of an integer literal of type int to the type int (that does not make great sense) and the sizeof operator is applied to the expression that yields the result of the type size_t.

In fact this expression is equivalent to

sizeof(int)

or in this particular case to

sizeof(123)

because the integer literal 123 has the type int.

The form of the explicit conversion of the functional notation is valid only in C++. In C such a notation of conversion is absent.

What does sizeof(int(123)) mean?

3 个答案: