Question

我有一个有日文字符的xml。 Xml正在被正确编组，但是哪个jaxbUnmarshalling所有字符都被转换为'？' 请在下面找到代码： -

import javax.xml.bind.annotation.XmlAttribute;
import javax.xml.bind.annotation.XmlElement;
import javax.xml.bind.annotation.XmlRootElement;

@XmlRootElement
public class Customer {

    String name;
    int age;
    int id;

    public String getName() {
        return name;
    }

    @XmlElement
    public void setName(String name) {
        this.name = name;
    }

    public int getAge() {
        return age;
    }

    @XmlElement
    public void setAge(int age) {
        this.age = age;
    }

    public int getId() {
        return id;
    }

    @XmlAttribute
    public void setId(int id) {
        this.id = id;
    }
}

JAXBExample

import java.io.File;
import javax.xml.bind.JAXBContext;
import javax.xml.bind.JAXBException;
import javax.xml.bind.Marshaller;

public class JAXBExample {
    public static void main(String[] args) {

      Customer customer = new Customer();
      customer.setId(100);
      customer.setName("株式会社三菱東京UFJ銀行");
      customer.setAge(29);

      try {

        File file = new File("C:\\file.xml");
        JAXBContext jaxbContext = JAXBContext.newInstance(Customer.class);
        Marshaller jaxbMarshaller = jaxbContext.createMarshaller();

        // output pretty printed
        jaxbMarshaller.setProperty(Marshaller.JAXB_ENCODING,"UTF-8");
        jaxbMarshaller.setProperty(Marshaller.JAXB_FORMATTED_OUTPUT, true);

        jaxbMarshaller.marshal(customer, file);
        jaxbMarshaller.marshal(customer, System.out);

          } catch (JAXBException e) {
        e.printStackTrace();
          }
    }
}

Conversion.java

public class Conversion {
    public static void main(String[] args) {
        try {
            File file = new File("C:\\file.xml");
            JAXBContext jaxbContext = JAXBContext.newInstance(Customer.class);
            Unmarshaller jaxbUnmarshaller = jaxbContext.createUnmarshaller();
            Customer customer = (Customer) jaxbUnmarshaller.unmarshal(file);
            System.out.println(customer.getName());

        } catch (JAXBException e) {
            e.printStackTrace();
        }
    }
}

OutPUT： -

XML： -

<?xml version="1.0" encoding="UTF-8" standalone="yes"?>
<customer id="100">
    <age>29</age>
    <name>株式会社三菱東京UFJ銀行</name>
</customer>

运行Conversion.java类后，我得到以下输出： -

客户名称？UFJ ??

请帮助我搜索网但找不到任何解决方案。

Answer 1

尝试使用正确的编码自行构建Reader并将Reader提供给Unmarshaller#unmarshal()，而不是File：

File file = new File("C:\\file.xml");
try (Reader reader = new InputStreamReader(new FileInputStream(file), "utf-8")) {
    try {
        JAXBContext jaxbContext = JAXBContext.newInstance(Customer.class);
        Unmarshaller jaxbUnmarshaller = jaxbContext.createUnmarshaller();
        Customer customer = (Customer) jaxbUnmarshaller.unmarshal(reader);
        System.out.println(customer.getName());

    } catch (JAXBException e) {
        e.printStackTrace();
    }
}

此外，如果您的平台编码类似于latin1，那么System.out会使用它并破坏正在输出的数据（将其替换为问号）。请运行您的程序：

java -Dfile.encoding=utf-8 JAXBExample

顺便说一下，如果没有Reader相关的扭曲，这可能就足以解决问题，因为unmarshal()方法应该尊重XML文件中指定的编码。

jaxbUnmarshaller无法解开日文字符

1 个答案: