Question

我有一份技术人员名单及其患者人数，当我点击技术人员时，我会得到患者名单及其详细信息。为此，我有查询返回每个技术人员的患者数量，另一个返回患者的记录。

SELECT *, SUM(Rcount) as Number_of_patients
FROM
(           
    SELECT users.users_id, users.name, patients.patients_id, count(*) as Rcount 
    FROM pecs 
    INNER JOIN users ON pecs.techniciens_id = users.users_id 
    INNER JOIN titles ON users.titles_id = titles.titles_id 
    INNER JOIN patients ON patients.patients_id = pecs.patients_id 
    GROUP BY users_id 
    UNION ALL
    SELECT users.users_id, users.name, patients.patients_id, count(*) as Rcount
    FROM followup 
    INNER JOIN users ON followup.technician_id = users.users_id 
    INNER JOIN titles ON users.titles_id = titles.titles_id 
    INNER JOIN pecs ON pecs.pecs_id = followup.pecs_id 
    INNER JOIN patients ON patients.patients_id = pecs.patients_id 
    GROUP BY users_id
)x 
GROUP BY users_id ORDER BY last_name ASC

结果是：

users_id    |   name    | Number_of_patients
40          |   ABABAB  | 223

这是223名技术员_ID = 40

的患者

现在，要查看此技术人员的患者列表，我有以下疑问：

SELECT *
FROM
(
    SELECT patients.patients_id, patients.name
    FROM pecs 
    LEFT JOIN users ON pecs.techniciens_id = users.users_id  
    LEFT JOIN titles ON users.titles_id = titles.titles_id 
    INNER JOIN patients ON patients.patients_id = pecs.patients_id 
    WHERE pecs.techniciens_id = 40
    #GROUP BY patients_id
    UNION ALL       
    SELECT patients.patients_id, patients.name
    FROM followup 
    LEFT JOIN users ON followup.technician_id = users.users_id 
    LEFT JOIN titles ON users.titles_id = titles.titles_id 
    LEFT JOIN pecs ON pecs.pecs_id = followup.pecs_id 
    INNER JOIN patients ON patients.patients_id = pecs.patients_id 
    WHERE followup.technician_id = 40
    #GROUP BY patients_id
)x
GROUP BY patients_id ORDER BY last_name ASC

现在，我获得了相同数量的记录（223），但是有一排重复的患者...我需要帮助，了解如何为每位技术人员获得正确数量的患者而无需重复。

有人可以帮忙吗？

Answer 1

我不确定我完全理解你的问题。无论如何，我会尽量让事情尽可能简单。关于你的“计数”查询，你可以从这样的东西开始，在那里我删除了我认为不应该用于计数的文件。这个查询应该给你计数避免多个id（我在两个select和UNION中使用DISTINCT来删除两个select之间可能的重复）。可能是某些连接可以被淘汰（但我不知道整个结构）。请关注Tim B.关于发布问题的格式和关注的建议。

SELECT USERS_ID, COUNT(*) AS PATIENTS_COUNT
FROM (
        SELECT DISTINCT USERS.USERS_ID, PATIENTS.PATIENTS_ID
        FROM PECS
        INNER JOIN USERS ON PECS.TECHNICIENS_ID = USERS.USERS_ID
        INNER JOIN TITLES ON USERS.TITLES_ID = TITLES.TITLES_ID
        INNER JOIN PATIENTS ON PATIENTS.PATIENTS_ID = PECS.PATIENTS_ID
        UNION 
        SELECT DISTINCT USERS.USERS_ID, PATIENTS.PATIENTS_ID 
        FROM FOLLOWUP
        INNER JOIN USERS ON FOLLOWUP.TECHNICIAN_ID = USERS.USERS_ID
        INNER JOIN TITLES ON USERS.TITLES_ID = TITLES.TITLES_ID
        INNER JOIN PECS ON PECS.PECS_ID = FOLLOWUP.PECS_ID
        INNER JOIN PATIENTS ON PATIENTS.PATIENTS_ID = PECS.PATIENTS_ID
    ) A

如何解决联合查询中记录数量的差异

1 个答案: