Question

HTML代码：

      <table width="409" border="1">
        <tr>
            <td><strong>Employee Name:</strong></td>  
             <th scope="col" align="left">             
            <select name="empid" id="empid">

          <option></option>
            <?php
          while($row = @mysql_fetch_array($result)) 
            {
       echo " <option value='$row[employeeid]'> $row[employeename] </option>";
            }
             ?>
           </select>
          </td>
          </tr>
        <!-- <tr>
            <td><strong>Employee Name:</strong></td>
            <th scope="col" align="left">
            <select name="employeename" id="employeename">
            <option></option>
          <?php
          while($row = @mysql_fetch_array($queryb)) 
            {
               echo "<option value='". $row['employeeid'] . "'>" . $row['fullname']."</option>"; 
            }
            ?>
         </select>
         </td></th>
         </tr>-->
           <!--   <tr>
            <td><strong>Date:</strong></td>
            <th scope="col" align="left">
             <input type="date" name="date" id="date" />
          </tr>-->
          <tr>
            <th scope="row">&nbsp;</th>
            <td>&nbsp;</td>
          </tr>
          <tr>
            <th scope="row">&nbsp;</th>
            <td><input type="submit" name="submitsearch" id="submitsearch" value="Search" /></td>
          </tr>
        </table>

如果我想点击搜索按钮并以这种方式生成结果。

EnNo TotalHours 12 HH：MM 28 HH：MM

数据库表视图：没有EnNo INOUT DateTime 1 12 S 2017-06-02 08:35 2 28 S 2017-06-02 10:10 3 28 E 2017-06-02 13:00 4 12 E 2017-06-02 14:02 5 12 S 2017-06-02 15:03 6 12 E 2017-06-02 19:04

我的查询是：

$ resultatt =＆＃34; SELECT EnNo，SEC_TO_TIME（SUM（TIME_TO_SEC（DateTime）））AS Totalhours FROM dataimport其中EnNo =＆＃39; $ _ POST [empid]＆＃39; GROUP BY EnNo＆＃34 ;;

但结果不是产生的?????????????????????

Answer 1

您需要更改查询，如下所示：

$resultatt = "SELECT EnNo,SEC_TO_TIME(SUM(TIME_TO_SEC(`DateTime`))) AS  
Totalhours FROM dataimport where EnNo = '$_POST[empid]' GROUP BY EnNo"; //IF you need single record only

或

$resultatt = "SELECT EnNo,SEC_TO_TIME(SUM(TIME_TO_SEC(`DateTime`))) AS Totalhours FROM dataimport GROUP BY EnNo"; //IF you need all records group by employee

Answer 2

try the below query

$resultatt = "SELECT EnNo,SEC_TO_TIME(SUM(TIME_TO_SEC(`DateTime`))) AS  
Totalhours FROM dataimport where EnNo = '".$_POST[empid]."' GROUP BY EnNo";

Answer 3

我刚刚创建了一个名为dataimport

的临时表

Table Format

并写了一个查询，

SELECT EnNo，work_dt， SEC_TO_TIME（sum（TIMESTAMPDIFF（SECOND，登录，注销）））作为time_worked 来自（选择EnNo，日期（DateTime）作为work_dt，DateTime作为登录，合并（（选择MIN（DateTime）从dataimport起b 在哪里a.EnNo = b.EnNo 和日期（a。DateTime）=日期（b。DateTime）和b。DateTime＆gt; = a。DateTime 和b。INOUT =＆＃39; E＆＃39; ），now（））AS注销来自dataimport AS 在哪里。INOUT =＆＃39; S＆＃39; ）作为t GROUP BY EnNo，work_dt

最后输出为

Output

希望这就是你所看到的。

查询无效

3 个答案: