过滤Firebase数据Swift 3

Question

我正在使用firebase来存储将在表格视图中显示的信息。这是数据库的屏幕截图：

我试图只添加来自某个“createdBy uid”的媒体：

    func fetchMyMedia() {
        let ref = DatabaseReference.media.reference()
        let query = ref.queryOrdered(byChild: "createdBy/uid").queryEqual(toValue: "Cdxbj1iCZUNxWRbIBllBxKqXh5P2")

        query.observe(.value, 
                      with: { snapshot in
                          for childSnapshot in snapshot.children {
                              self.myMedia.insert(childSnapshot as! Media, at: 0)
                              let indexPath = IndexPath(row: 0, section: 0)
                          }
                      })
    }

“myMedia”是Media

类型的数组

我收到错误，我无法将FIRDataSnapshot类型的值转换为XXXXXX.Media。对此的任何帮助将不胜感激。

如果它有帮助，没有列出我的整个Model类，这就是我如何得到所有未经过滤的信息......

    extension Media {
        class func observeNewMedia(_ completion: @escaping (Media) -> Void) {
            DatabaseReference.media.reference().observe(.childAdded, with: { snapshot in
                let media = Media(dictionary: snapshot.value as! [String : Any])
                completion(media)
            })
        }

然后......

    func fetchMedia() {
            Media.observeNewMedia { (media) in
                if !self.media.contains(media) {
                    self.media.insert(media, at: 0)
                    self.tableView.reloadData()
                }
            }
        }

Answer 1

    func fetchMyMedia() {
        let ref = DatabaseReference.media.reference()
        let query = ref.queryOrdered(byChild: "createdBy/uid").queryEqual(toValue: "Cdxbj1iCZUNxWRbIBllBxKqXh5P2")

       query.observe(.childAdded, with: { snapshot in

                let media = Media(dictionary: snapshot.value as! [String : Any])
                self.myMedia.insert(media, at: 0)
            self.tableView.reloadData()