Question

您好我有一个SQL Server表，其中一列有逗号分隔值：

12323,234322,1112,99323.....

我有一个参数@values nvarchar(500)，它也会有逗号分隔值。

在我的查询中，我需要检查表格字段中是否存在参数中的任何内容。

像这样的＆gt;

...
WHERE 
(@values = '' OR select s from dbo.Split(',',t.Data) in ( select s from dbo.Split(',',@values )))

当然上面给我的错误。

有任何线索吗？

Answer 1

加入你从分裂中获得的两个表

SELECT *
...
FROM (SELECT s FROM dbo.Split(',',t.Data)) X
INNER JOIN (SELECT s FROM dbo.Split(',',@values)) Y
ON X.s = Y.s
...

Answer 2

EXISTS是你的朋友。

 WHERE 
(@values = '' OR EXISTS (select a.value from string_split(t.Data, ',') a inner join ( select value from string_split(@values, ',')) b ON a.value = b.value))

Answer 3

尝试以下代码，它可能会帮助您

IF OBJECT_ID('Tempdb..#Temp') IS NOT NULL
Drop table #Temp

Declare @SearchVariable varchar(1000)='12323,234322,1112,99323,22222,4545,656565,8989,1111,22222'--Varibale Contains these values to search

CREATE TABLE #Temp (CommaValue Varchar(100))-- This is the table having comma separted value columns
INSERT INTO #Temp
SELECT '12323,234322,1112,99323' Union all
SELECT '12323,656565,1112,4545'

Declare @VariableSearch TABLE (ValueName varchar(1000))
Insert into @VariableSearch

SELECT @SearchVariable
;With cte
AS
(
SELECT Split.a.value('.', 'VARCHAR(1000)') AS TablesData
            FROM (
                SELECT CAST('<S>' + REPLACE(CommaValue, ',', '</S><S>') + '</S>' AS XML) AS TablesData
                FROM #Temp
                ) AS A
            CROSS APPLY TablesData.nodes('/S') AS Split(a)
)
SELECT DISTINCT ROW_NUMBER()Over(Order by (SELECT 1)) AS Rno, * from cte C Inner join
(
SELECT Split.a.value('.', 'VARCHAR(1000)') AS VariableSeachData
            FROM (
                SELECT CAST('<S>' + REPLACE(ValueName, ',', '</S><S>') + '</S>' AS XML) AS VariableSeachData
                FROM @VariableSearch
                ) AS A
            CROSS APPLY VariableSeachData.nodes('/S') AS Split(a)
            )DT
            On  C.TablesData=DT.VariableSeachData

输出

Rno TablesData  VariableSeachData
---------------------------------
1       1112            1112
2       1112            1112
3       12323           12323
4       12323           12323
5       234322          234322
6       4545            4545
7       656565          656565
8       99323           99323

Answer 4

不太确定，但也许这可以给你一个想法。

使用Outer Apply和EXISTS运算符。

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SQL选择Split列然后在其他split select中查找

4 个答案: