Question

我有一个包含此格式矩阵的文本文件：http://textuploader.com/d0qmb 每个整数必须在矩阵中占据自己的位置。我编写了这段代码，允许我为矩阵中的每一行打印数组，但我不知道如何附加每个数组来创建矩阵。

import numpy as np

# rows, cols not used in code. Just for info
rows = 9
cols = 93

with open('bob.txt') as f:
 while True:
    i=0
    str = f.readline()
    str = str.strip()
    d = list(str)
    d = map(int, d)
    if not str: break
    print(d)
    i += 1

Answer 1

import numpy as np

array = []
with open('bob.txt', 'r') as f:
    for line in f:
        array.append(array.append([int(i) for i in list(line) if i.isdigit()]))

numpy_array = np.array(array)

python中的

[int(i) for i in list(line) if i.isdigit()]为a list comprehension。

它大致相同：

for character in line:
    if character is:
        cast this character to an int and append it to the list

在文本文件中追加行以在python中生成矩阵

1 个答案: