我有一段由List组成的数据,而List又有一个List。如何显示特定的LeafSide? p>
视图模型:
private List<Leaf> _Leaves = new List<Leaf>();
public List<Leaf> Leaves
{
get { return _Leaves; }
set
{
_Leaves = value;
NotifyPropertyChanged();
}
}
数据结构:
class Leaf : NotifyBase
{
private string _LeafNo;
public string LeafNo
{
get { return _LeafNo; }
set
{
_LeafNo = value;
NotifyPropertyChanged();
}
}
private List<LeafSide> _Side = new List<LeafSide>();
public List<LeafSide> Side
{
get { return _Side; }
set
{
_Side = value;
NotifyPropertyChanged();
}
}
//More stuff
}
class LeafSide : NotifyBase
{
private string _Notes;
public string Notes
{
get { return _Notes; }
set
{
_Notes = value;
NotifyPropertyChanged();
}
}
//More stuff
}
查看:
<DataGrid ItemsSource="{Binding Leaves}">
<DataGrid.Columns>
<DataGridTextColumn Width="auto" MinWidth="50" Header="Notes" Binding="{Binding Side/Notes}"/>
<DataGridTextColumn Width="50" Header="Punch" Binding="{Binding Side/Punch}"/>
<!--More-->
</DataGrid.Columns>
上面的DataGrid将显示第一个完美的LeafSide,但我不能为我的生活弄清楚如何让它显示第二面。我可以找到DataGrids和嵌套列表的所有示例都是显示列表中的特定值。 我期待像
这样的东西<DataGridTextColumn Width="auto" MinWidth="50" Header="Notes" Binding="{Binding Side[1]/Notes}"/>
工作,但事实并非如此。
编辑更多信息: 我需要DataGrid来显示: Seperate DataGrids for Leaf and LeafSide[0] displayed 而且对于LeafSide [1]
答案 0 :(得分:0)
我建议创建一个名为&#39; SelectedSide&#39;在Leaf&#39; Leaf&#39;并使用那个来绑定
private LeafSide _selectedSide;
public LeafSide SelectedSide
{
get { return _selectedSide; }
set { _selectedSide = value; NotifyPropertyChanged("SelectedSide"); }
}
我想&#39; [1]&#39;与LeafNo有关。如果是这样,设置SelectedSide = Sides [LeafNo]
<DataGridTextColumn Width="auto" MinWidth="50" Header="Notes" Binding="{Binding SelectedSide.Notes}"/>
答案 1 :(得分:0)
ASh提供了答案,只是重新发布,所以我可以标记为已回答
从右强> {Binding Side [1] .Notes}
<强> WRONG 强> {Binding Side [1] / Notes}