Question

我需要使用X Query从XML获取属性值。但这个属性就像Processing指令一样。那么如何处理这种部分？

using System;
using System.Collections.Concurrent;
using System.Collections.Generic;
using System.Threading;
using System.Threading.Tasks;
using System.Windows.Forms;

namespace WindowsFormsApplication1
{
    public partial class Form1 : Form
    {
        ConcurrentQueue<string> messageQueue = new ConcurrentQueue<string> ();

        public Form1 ()
        {
            InitializeComponent ();
        }

        private async void Form1_Load (object sender, EventArgs e)
        {
            var task1 = GetMessages ();
            var task2 = Task.Factory.StartNew (GetOrderBookData);

            dgOrders.DataSource = await task2;

            await Task.WhenAll (task1, task2);

            UpdateOrderBook ();
        }


        public async Task GetMessages ()
        {
            for (int i = 0; i < 10; i++)
            {
                string message = await Task.Run (() => GetMessage (i));

                messageQueue.Enqueue (message);
                listBox1.Items.Add (message);
            }
        }


        private string GetMessage (int id)
        {
            Thread.Sleep (500); // simulate work
            return "some-message-" + id;
        }


        private IReadOnlyList<string> GetOrderBookData ()
        {
            Thread.Sleep (2000); // simulate work

            return new List<string> { "order 1", "order 2", "order 3" };
        }


        private void UpdateOrderBook ()
        {
            string message = null;

            string jsonString;

            while (messageQueue.TryDequeue (out jsonString))
            {
                message += jsonString + "\r\n";
            }

            MessageBox.Show (message);
        }
    }
}

Answer 1

如果它看起来像处理指令那么它就是。

对于特定的处理指令，请指定目标。

data(//processing-instruction(test))

所有处理说明

data(//processing-instruction())

Marklogic - 如何处理XML中的处理指令

1 个答案: